The correct order of size of the given species is: 

The correct statement about the radius of a species is :

The correct order of the decreasing ionic radii among the following isoelectronic species is:

1. $C{a}^{2+}>K^{+}>S^{2-}>C{l}^{-}$

2. $C{l}^{-}>S^{2-}>C{a}^{2+}>K^{+}$

3. $S^{2-}>C{l}^{-}>K^{+}>C{a}^{2+}$

4. $K^{+}>C{a}^{2+}>C{l}^{-}>S^{2-}$

Match the following isoelectronic species in Column I and Column II: 

Among the following species, the smallest ion is : 

The correct sequence of increasing radii is - 

In alkaline earth metals, the properties, from the following, that will increase from Be to Ba are-

(i) Atomic radius       
(ii) Ionisation energy       
(iii) Nuclear charge

A common trend in both groups I and II elements in the periodic table, as the atomic number increases, is :

1. Oxidizing power increases

2. Atomic radius increases

3. Maximum valency increases

4. Reactivity with water decreases

Increasing order of ionic radii and decreasing order of number of protons of the given isoelectronic species is:-

1. Ca⁺², K⁺, Cl^-, S^-2

2. Cl^-, Ca⁺², K⁺, S^-2

3. S^-2, Cl^-, Ca⁺², K⁺

4. None of the above

The correct order of ionic radii is:

1. $H^{-}>H^{+}>H$ $$
2. $N{a}^{+}>F^{-}>O^{2-}$
3. $F^{-}>O^{2-}>N{a}^{+}$
4. $N^{3-}>M{g}^{2+}>A{l}^{3+}$