The formation of the oxide ion O2– (g), from the oxygen atom requires first an exothermic and then an endothermic step as shown below,
Thus, the process of formation of O2– in the gas phase is unfavorable even though O2– is isoelectronic with neon. It is due to the fact that:
1. | Electron repulsion outweighs the stability gained by achieving noble gas configuration. |
2. | O– ion has a comparatively smaller size than the oxygen atom. |
3. | Oxygen is more electronegative. |
4. | Addition of electrons in oxygen results in a large size of the ion. |
The species Ar, K+ and Ca2+ contain the same number of electrons. In which order do their radii increase?
1. Ar < K+ < Ca2+
2. Ca2+ < Ar < K+
3. Ca2+ < K+ < Ar
4. K+ < Ar < Ca2+
The correct order of ionic radii is:
1.
2.
3.
4.
Be2+ is isoelectronic with which of the following ions?
1.
2.
3.
4.
The correct order of the decreasing ionic radii among the following isoelectronic species is:
1.
2.
3.
4.
The correct order of increasing electron affinity for the elements, O, S, F and Cl is:
1. | Cl < F < O < S | 2. | O < S < F < Cl |
3. | F < S < O < Cl | 4. | S < O < Cl < F |
Amongst the elements with the following electronic configurations, which one of them may have the highest ionisation energy?
1.
2.
3.
4.
1. Cr > Mn > V > Ti
2. V > Mn > Cr > Ti
3. Mn > Cr > Ti > V
4. Ti > V > Cr > Mn
Which one of the following arrangements does not give the correct picture of the trends indicated against it?
1. F2> Cl2> Br2> I2 : Oxidising power
2. F<Cl>Br>I : Electron gain enthalpy
3. F2> Cl2> Br2> I2 : Bond dissociation energy
4. F> Cl > Br > I : Electronegativity
Among the following, the most characteristic oxidation states for lead and tin are, respectively:
1. +4, +2
2. +2, +4
3. +4, +4
4. +2, +2