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A dielectric slab is inserted between the plates of an isolated charged capacitor. Which of the following quantities will remain the same?
| (a) | the electric field in the capacitor |
| (b) | the charge on the capacitor |
| (c) | the potential difference between the plates |
| (d) | the stored energy in the capacitor |
Choose the correct option:
1. (a), (b)
2. (b) only
3. (c), (a)
4. (a), (d)
Subtopic: Â Dielectrics in Capacitors |
 78%
Level 2: 60%+
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The left plate \(A\) of an air capacitor is connected to the positive terminal while the right plate \(B\) is connected to the negative terminal of a cell of voltage \(V_0.\) Assume that the plate area is \(A,\) and the plate separation is \(d.\) If a slab of dielectric constant \(K\) is inserted into the space between the plates, the electric field in the dielectric will be: (compared to the air capacitor)
| 1. | more. |
| 2. | less. |
| 3. | equal. |
| 4. | more or less or equal depending on the value of \(K\). |
Subtopic: Â Dielectrics in Capacitors |
Level 3: 35%-60%
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