Two slits in Young's experiment have widths in the ratio of \(1:25\). The ratio of intensity at the maxima and minima in the interference pattern \(\frac{I_{\text{max}}}{I_{\text{min}}}\) is:
1. \(\dfrac{9}{4}\) 2. \(\dfrac{121}{49}\)
3. \(\dfrac{49}{121}\) 4. \(\dfrac{4}{9}\)
Subtopic:  Young's Double Slit Experiment |
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NEET - 2015
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In Young's double-slit experiment, the slits are separated by \(0.28\) mm and the screen is placed \(1.4\) m away. The distance between the first dark fringe and the fourth bright fringe is obtained to be \(0.6\) cm. The wavelength of the light used in the experiment is:
1. \(3.4 \times 10^{-7}~\text{m}\)
2. \(4.1 \times 10^{-7}~\text{m}\)
3. \(3.4 \times 10^{-9}~\text{m}\)
4. \(4.1 \times 10^{-9}~\text{m}\)

Subtopic:  Young's Double Slit Experiment |
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From NCERT
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