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Q. No.The current in a wire varies with time according to the equation \(I=(4+2t),\) where \(I\) is in ampere and \(t\) is in seconds. The quantity of charge which has passed through a cross-section of the wire during the time \(t=2\) s to \(t=6\) s will be:
| 1. | \(60\) C | 2. | \(24\) C |
| 3. | \(48\) C | 4. | \(30\) C |
Subtopic: Current & Current Density |
84%
Level 1: 80%+
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The current in a wire varies with time according to the relation \(i = (3+2t)~\text{A}\). The amount of charge passing a cross section of the wire in the time interval \(t=0\) to \(t = 4.0~\text{s}\) would be: (where \(t\) is time in seconds)
| 1. | \(28\) C | 2. | \(30.5\) C |
| 3. | \(8\) C | 4. | \(82\) C |
Subtopic: Current & Current Density |
86%
Level 1: 80%+
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A student measures the terminal potential difference \(V\) of a cell (of emf \( E\) and internal resistance \(r\)) as a function of the current \(I\) flowing through it. The slope and intercept of the graph between \(V\) and \(I,\) respectively, is equal to:
1. \(E\) and \(-r\)
2. \(-r\) and \(E\)
2. \(-r\) and \(E\)
3. \(r\) and \(-E\)
4. \(-E\) and \(r\)
Subtopic: EMF & Terminal Voltage |
70%
Level 2: 60%+
AIPMT - 2009
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The magnitude and direction of the current in the following circuit is:
| 1. | \(1.5~\text{A}\) from \({B}\) to \({A}\) through \(E\) |
| 2. | \(0.2~\text{A}\) from \({B}\) to \({A}\) through \(E\) |
| 3. | \(0.5~\text{A}\) from \({A}\) to \({B}\) through \(E\) |
| 4. | \(\dfrac{5}{9}~\text{A}\) from \({A}\) to \({B}\) through \(E\) |
Subtopic: Kirchoff's Voltage Law |
75%
Level 2: 60%+
NEET - 2023
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\(10\) resistors, each of resistance \(R\) are connected in series to a battery of \(E\) and negligible internal resistance. Then those are connected in parallel to the same battery, the current is increased \(n\) times. The value of \(n\) is:
1. \(1000\)
2. \(10\)
3. \(100\)
4. \(1\)
1. \(1000\)
2. \(10\)
3. \(100\)
4. \(1\)
Subtopic: Combination of Resistors |
69%
Level 2: 60%+
NEET - 2023
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A wire of length \('l'\) and resistance \(100 ~\Omega\) is divided into \(10\) equal parts. The first \(5\) parts are connected in series while the next \(5\) parts are connected in parallel. The two combinations are again connected in series. The resistance of this final combination is:
| 1. | \(52~ \Omega\) | 2. | \(55~ \Omega\) |
| 3. | \(60 ~\Omega\) | 4. | \(26~ \Omega\) |
Subtopic: Combination of Resistors |
68%
Level 2: 60%+
NEET - 2024
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Arrange the following in the order of their resistance.
Choose the correct answer from the options given below:
| A. | (\(0\) to \(1~\text A\)) ranged ammeter. |
| B. | (\(0\) to \(100~\text {mA}\)) ranged milli-ammeter. |
| C. | (\(0\) to \(500~\mu\text A\)) ranged micro-ammeter. |
| D. | (\(0\) to \(100~\text V\)) ranged voltmeter. |
Choose the correct answer from the options given below:
| 1. | \(\mathrm{A > B > C > D}\) | 2. | \(\mathrm{D > C > B > A}\) |
| 3. | \(\mathrm{D > A > B > C}\) | 4. | \(\mathrm{C > B > A > D}\) |
Subtopic: Derivation of Ohm's Law |
54%
Level 3: 35%-60%
NEET - 2024
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In an electrical circuit, the voltage is measured as \({V}=(200\pm4)\) volts and the current is measured as \({I}=(20\pm0.2)~\text A.\) The value of the resistance is:
| 1. | \((10\pm4.2)~\Omega \) | 2. | \((10\pm0.3)~\Omega \) |
| 3. | \((10\pm0.1)~\Omega \) | 4. | \((10\pm0.8)~\Omega \) |
Subtopic: Derivation of Ohm's Law |
50%
Level 3: 35%-60%
NEET - 2024
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The steady-state current in the circuit shown below is:
| 1. | \(0.67~\text A\) | 2. | \(1.5~\text A\) |
| 3. | \(2~\text A\) | 4. | \(1~\text A\) |
Subtopic: Derivation of Ohm's Law |
72%
Level 2: 60%+
NEET - 2024
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The resistance of a wire is \(R\) ohm. If it is melted and stretched to \(n\) times its original length, its new resistance will be:
| 1. | \(nR\) | 2. | \(\frac{R}{n}\) |
| 3. | \(n^2R\) | 4. | \(\frac{R}{n^2}\) |
Subtopic: Derivation of Ohm's Law |
83%
Level 1: 80%+
NEET - 2017
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