The equivalent capacitance between \(A\) and \(B\) is:

         

1. \(2~\mu\text{F}\) 2. \(3~\mu\text{F}\)
3. \(5~\mu\text{F}\) 4. \(0.5~\mu\text{F}\)
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Five identical plates each of area \(A\) are joined as shown in the figure. The distance between the plates is \(d\). The plates are connected to a potential difference of \(V\) volts. The charge on plates \(1\) and \(4\) will be:

        
1. \(-\frac{\varepsilon_{0} A V}{d} ,  \frac{2\varepsilon_{0} A V}{d}\)
2. \(\frac{\varepsilon_{0} A V}{d} ,  \frac{2\varepsilon_{0} A V}{d}\)
3. \(\frac{\varepsilon_{0} A V}{d} , -\frac{2\varepsilon_{0} A V}{d}\)
4. \(-\frac{\varepsilon_{0} A V}{d} ,  -\frac{2\varepsilon_{0} A V}{d}\)

Subtopic:  Combination of Capacitors |
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Three capacitors each of capacity \(4\) µF are to be connected in such a way that the effective capacitance is \(6\) µF. This can be done by:

1.  connecting all of them in a series.
2. connecting them in parallel.
3. connecting two in series and one in parallel.
4. connecting two in parallel and one in series.

Subtopic:  Combination of Capacitors |
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AIPMT - 2003
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Three capacitors, each of capacitance \(0.3~\mu \text{F}\) are connected in parallel. This combination is connected with another capacitor of capacitance \(0.1~\mu \text{F}\) in series. Then the equivalent capacitance of the combination is:
1. \(0.9~\mu\text{F}\) 2. \(0.09~\mu\text{F}\)
3. \(0.1~\mu\text{F}\) 4. \(0.01~\mu\text{F}\)
Subtopic:  Combination of Capacitors |
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Four capacitors each of capacity \(3~\mu\text{F}\) are connected as shown in the adjoining figure. The ratio of equivalent capacitance between \(A\) and \(B\) and between \(A\) and \(C\) will be:

       

1. \(4:3\)

2. \(3:4\)

3. \(2:3\)

4. \(3:2\)

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The equivalent capacitance between the points \(A\) and \(B\) in the given network is:

       

1. \(25~\mu\text{F}\)
2. \(16~\mu\text{F}\)
3. \(21~\mu\text{F}\)
4. \(12~\mu\text{F}\)

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In the given circuit if point \(C\) is connected to the earth and a potential of \(+2000~\text{V}\) is given to the point \(A\), the potential at \(B\) is:
             

1. \(1500\) V 2. \(1000\) V
3. \(500\) V 4. \(400\) V
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A network of four capacitors of capacity equal to \(C_1 = C, C_2 = 2C, C_3 = 3C\) and \(C_4 = 4C\) are connected in a battery as shown in the figure. The ratio of the charges on \(C_2\) and \(C_4\) is:
         
1. \(\frac{22}{3}\)
2. \(\frac{3}{22}\)
3. \(\frac{7}{4}\)
4. \(\frac{4}{7}\)

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The equivalent capacitance between points \(a\) and \(b\) in the network shown below is:

                          

1. \(5~\text{C}\)
2. \(4~\text{C}\)
3. \(3~\text{C}\)
4. \(2~\text{C}\)

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Two capacitors of capacitance \(6~\mu\text{F}\) and \(3~\mu\text{F}\) are connected in series with battery of \(30~\text{V}\). The charge on \(3~\mu\text{F}\) capacitor is:
          
1. \( 3 ~\mu\text{C}\)
2. \( 1.5 ~\mu\text{C}\)
3. \( 60~\mu\text{C}\)
4. \( 900~\mu\text{C}\)

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