In a stationary wave along a string, the strain is:
1. zero at the antinodes
2. maximum at the antinodes
3. zero at the nodes
4. maximum at the nodes
1. | \(100~\text{times}\) | 2. | \(50~\text{times}\) |
3. | \(200~\text{times}\) | 4. | \(400~\text{times}\) |
1. | \(l\) | 2. | \(2l\) |
3. | \(3l\) | 4. | \(4l\) |
1. | Wavelength of the component waves is \(10~\text{cm}.\) |
2. | The separation between a node and the nearest antinode is \(2.5~\text{cm}.\) |
3. | Frequency of the component wave is \(0.25~\text{Hz}\). |
4. | All of these |
Assertion (A): | A glass tube partially filled with water represents an open organ pipe. |
Reason (R): | The open end corresponds to an antinode and the end in contact with water, to a node. |
1. | Both (A) and (R) are True and (R) is the correct explanation of (A). |
2. | Both (A) and (R) are True and (R) is not the correct explanation of (A). |
3. | (A) is True but (R) is False. |
4. | (A) is False but (R) is True. |
A string of length \(3\) m and a linear mass density of \(0.0025\) kg/m is fixed at both ends. One of its resonance frequencies is \(252\) Hz. The next higher resonance frequency is \(336\) Hz. Then the fundamental frequency will be:
1. \(84~\text{Hz}\)
2. \(63~\text{Hz}\)
3. \(126~\text{Hz}\)
4. \(168~\text{Hz}\)
The length of the string of a musical instrument is \(90\) cm and has a fundamental frequency of \(120\) Hz. Where should it be pressed to produce a fundamental frequency of \(180\) Hz?
1. | \(75\) cm | 2. | \(60\) cm |
3. | \(45\) cm | 4. | \(80\) cm |