In a stationary wave along a string, the strain is:
1. zero at the antinodes
2. maximum at the antinodes
3. zero at the nodes
4. maximum at the nodes

Subtopic:  Standing Waves |
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The equation of a standing wave in a string is \(y = (200~\text{m})\sin\left(\frac{2\pi}{50}x\right)\cos\left(\frac{2\pi}{0.01}t\right)\) where \(x\) is in metres and \(t\) is in seconds. At the position of antinode, how many times does the distance of a string particle become \(200~\text{m}\) from its mean position in one second?
1. \(100~\text{times}\) 2. \(50~\text{times}\)
3. \(200~\text{times}\) 4. \(400~\text{times}\)
Subtopic:  Standing Waves |
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The equation of a stationary wave is \(y = 0.8\cos\left(\frac{\pi x}{20}\right)\sin200(\pi t)\), where \(x\) is in \(\text{cm}\) and \(t\) is in \(\text{sec}.\) The separation between consecutive nodes will be:
1. \(20~\text{cm}\)
2. \(10~\text{cm}\)
3. \(40~\text{cm}\)
4. \(30~\text{cm}\)
Subtopic:  Standing Waves |
 78%
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The maximum possible wavelength in an open organ pipe of length \(l\) is:
1. \(l\) 2. \(2l\)
3. \(3l\) 4. \(4l\)
Subtopic:  Standing Waves |
 70%
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The equation of a stationary wave is given as \(y =A\sin(0.5\pi t)\cos(0.2\pi x)\) where \(t\) is in seconds and \(x\) in centimetres. Which of the following is correct?
1. Wavelength of the component waves is \(10~\text{cm}.\)
2. The separation between a node and the nearest antinode is \(2.5~\text{cm}.\)
3. Frequency of the component wave is \(0.25~\text{Hz}\).
4. All of these
Subtopic:  Standing Waves |
 90%
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A string of length \(l\) is fixed at one end and free at the other. If it resonates in different modes, then the ratio of frequencies is:
1. \(1:2:3:~.......\)
2. \(1:3:5:7~.......\)
3. \(1:2:4:8~.......\)
4. \(1:3:9:~.......\)
Subtopic:  Standing Waves |
 83%
From NCERT
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Given below are two statements:
Assertion (A): A glass tube partially filled with water represents an open organ pipe.
Reason (R): The open end corresponds to an antinode and the end in contact with water, to a node.
In the light of the above statements, choose the correct answer from the options given below:
1. Both (A) and (R) are True and (R) is the correct explanation of (A).
2. Both (A) and (R) are True and (R) is not the correct explanation of (A).
3. (A) is True but (R) is False.
4. (A) is False but (R) is True.
Subtopic:  Standing Waves |
 68%
From NCERT
NEET - 2024
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A string of length \(3\) m and a linear mass density of \(0.0025\) kg/m is fixed at both ends. One of its resonance frequencies is \(252\) Hz. The next higher resonance frequency is \(336\) Hz. Then the fundamental frequency will be:
1. \(84~\text{Hz}\)
2. \(63~\text{Hz}\)
3. \(126~\text{Hz}\)
4. \(168~\text{Hz}\)

Subtopic:  Standing Waves |
 78%
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Stationary waves are formed on a stretched string. If the wavelength is \(\lambda,\) then the distance between two points having the maximum displacement can be:
1. \(\frac{3\lambda}{2}\)
2. \(4\lambda\)
3. \(\frac{5\lambda}{2}\)
4. All of these

Subtopic:  Standing Waves |
 67%
From NCERT
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The length of the string of a musical instrument is \(90\) cm and has a fundamental frequency of \(120\) Hz. Where should it be pressed to produce a fundamental frequency of \(180\) Hz? 

1. \(75\) cm 2. \(60\) cm
3. \(45\) cm 4. \(80\) cm
Subtopic:  Standing Waves |
 84%
From NCERT
NEET - 2020
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