Total vapour pressure of a mixture of 1 mol A (pA°  = 150 torr) and 2 mol B (pB° = 240 torr) is 200 torr. In this case:-

1. There is a positive deviation from Raoult's law
2. There is a negative deviation from Raoult's law
3. There is no deviation from Raoult's law
4. None of these 

Subtopic:  Introduction & Colligative properties | Relative Lowering of Vapour Pressure |
 66%
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The vapour pressure of a pure liquid solvent A is 0.80 atm. When a non-volatile substance B is added to the solvent, its vapour pressure drops to 0.60 atm.
Mole fraction of the component B in the solution is:

1. 0.50 2. 0.75
3. 0.40 4. 0.25
Subtopic:  Relative Lowering of Vapour Pressure |
 73%
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The Vapour pressure of CCl4 at 25°C is 143 mm Hg. 0.5 g of a non-volatile solute (mol. wt. 65) is dissolved in 100 ml of CCl4. The vapor pressure of the solution is-

(Density of CCl= 1 .58 g/cm3) 

1. 141.93 mm Hg

2. 94.39 mm Hg

3. 199.34 mm Hg

4. 143.99 mm Hg

Subtopic:  Relative Lowering of Vapour Pressure |
 68%
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The equal weight of a solute is dissolved in an equal weight of two solvents A and B to form a very dilute solution. The relative lowering of vapour pressure for solution B has twice the relative lowering of vapour pressure for solution A.

If MA and MB are the molecular weights of solvents A and B respectively, then:

1. MA = MB

2. MB = 2MA

3. MA = 4MB

4. MA = 2MB

Subtopic:  Relative Lowering of Vapour Pressure |
 63%
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If 8 g of a non-electrolyte solute is dissolved in 114 g of n-octane to reduce its vapor pressure to 80 %, the molar mass (in g mol–1) of the solute is:

[Molar mass of n-octane is 114 g mol–1]

1. 40 2. 60
3. 80 4. 20
Subtopic:  Relative Lowering of Vapour Pressure |
 62%
From NCERT
NEET - 2020
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One mole of sugar is dissolved in three moles of water at 298 K. The relative lowering of vapour pressure is:

1. 0.25 2. 0.15
3. 0.50 4. 0.33
Subtopic:  Relative Lowering of Vapour Pressure |
 75%
From NCERT
NEET - 2022
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At 100 °C the vapour pressure of a solution of 6.5 g of a solute in 100 g water is 732 mm. If Kb = 0.52, the boiling point of this solution will be:
1. 100 oC
2. 102 oC
3. 103 oC
4. 101 oC
Subtopic:  Relative Lowering of Vapour Pressure | Elevation of Boiling Point |
 59%
From NCERT
NEET - 2016
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The largest freezing point depression among the following 0.10 m solutions is shown by:

1. \(\mathrm{KCl}\) 2. \(\mathrm{C_6H_{12}O_6}\)
3. \(\mathrm{Al}_2(\mathrm{SO_4})_3\) 4. \(\mathrm{K_2SO_4}\)
Subtopic:  Relative Lowering of Vapour Pressure |
 80%
From NCERT
AIPMT - 2014
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The incorrect statement among the following is:

1. Units of atmospheric pressure and osmotic pressure are the same.
2. In reverse osmosis, solvent molecules move through a semipermeable membrane from a region of lower concentration of solute to a region of higher concentration.
3. The value of molal depression constant depends on nature of solvent.
4. Relative lowering of vapour pressure, is a dimensionless quantity.

Subtopic:  Relative Lowering of Vapour Pressure | Elevation of Boiling Point | Depression of Freezing Point | Osmosis & Osmotic Pressure |
 68%
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The vapour pressure of water in the solution having 50 g of urea dissolved in 850 g of water is:

(Vapor pressure of pure water at 298 K is 23.8 mm Hg) 

1. 23.40 mm of Hg

2. 33.46 mm of Hg

3. 12.76 mm of Hg

4. 87.12 mm of Hg

Subtopic:  Relative Lowering of Vapour Pressure |
 73%
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