Sn⁺⁺ loses two electrons in a reaction. The final oxidation number of tin will be:

1. + 2

2. Zero

3. + 4

4. – 2

What is the alteration in the oxidation state of carbon in the given reaction?

\(\mathrm{{CH_4}_{(g)} + 4{Cl_2}_{(g)} \rightarrow {CCl_4}_{(l)} + 4 HCl_{(g)}}\)

From the following, identify the reaction having the top position in the EMF series (standard reduction potential) according to their electrode potential at 298 K.

1. Mg²⁺+ 2e^–$\to$Mg_(s)
2. Fe²⁺ + 2e^–$\to$ Fe_(s)
3. Au³⁺+ 3e^–$\to$Au_(s)
4. K⁺+ 1e ^–$\to$K_(s)

 The compound having oxygen in - 1 oxidation state is:-

The oxidation number of S in H₂S₂O₈ is:

1. + 2

2. + 4

3. + 6

4. + 7

Oxidation number of oxygen in potassium super oxide (KO₂) is:

1. – 2

2. – 1

3. – 1/2

4. – 1/4

The highest oxidation number of nitrogen among the following compounds is:

The oxidation number of oxygen in ${\mathrm{KO}}_3$ $\mathrm{and}$ ${\mathrm{Na}}_2{\mathrm{O}}_2$ is respectively -

1. 3, and 2
2. 1, and 0
3. 0, and 1
4. -0.33, and -1

Among the following the correct order of acidity is-

1. HClO < HClO₂< HClO₃< HClO₄
2. HClO₂< HClO < HClO₃< HClO₄
3. HClO₄< HClO₂< HClO < HClO₃
4. HClO₃< HClO₄< HClO₂< HClO