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Q. No.The number of lone pairs xenon has in XeF2, XeF4, and XeF6 is, respectively:
1. 3, 2, 1
2. 2, 4, 6
3. 1, 2, 3
4. 6, 4, 2
1. 3, 2, 1
2. 2, 4, 6
3. 1, 2, 3
4. 6, 4, 2
Subtopic: Group 18 - Preparation, Properties & Uses | Interhalogen Compounds |
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PCl3 and PCl5 both exist; NCl3 exists but NCl5 does not exist. It is due to:
| 1. | Lower electronegativity of P and N |
| 2. | Lower tendency of N to form a covalent bond |
| 3. | Availability of vacant d-orbital in P but not in N |
| 4. | The statement is incorrect |
Subtopic: Group 15 - Preparation, Properties & Uses |
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The substance used in Holmes signals of the ship is a mixture of :
1. CaC2 + Ca3P2
2. Ca3(PO4)2 + Pb3O4
3. H3PO4 + CaCl2
4. NH3 + HOCl
Subtopic: Group 15 - Preparation, Properties & Uses |
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| Statement I: | Fluorine forms only one oxoacid. |
| Statement II: | Fluorine forms three oxides OF2, O2F2, and O2F. |
| 1. | Both Statement I & Statement II are true. |
| 2. | Both Statement I & Statement II are false. |
| 3. | Statement I is true while Statement II is false. |
| 4. | Statement I is false while Statement II is true |
Subtopic: Group 17 - Preparation, Properties & Uses |
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The gas that is produced during the following reaction:
\(NH_{4}Cl + NaNO_{2} \xrightarrow[]{\Delta} Product\)
1. NH3
2. N2
3. Cl2
4. N2O
\(NH_{4}Cl + NaNO_{2} \xrightarrow[]{\Delta} Product\)
1. NH3
2. N2
3. Cl2
4. N2O
Subtopic: Group 15 - Preparation, Properties & Uses |
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PCl5 is formed whereas NCl5 is not formed because:
| 1. | Phosphorous has vacant d-orbitals while nitrogen does not have vacant d-orbitals. |
| 2. | PCl5 is stable while NCl5 is unstable. |
| 3. | Phosphorous is more reactive while nitrogen is inert. |
| 4. | Phosphorous has a large size while nitrogen has a small size. |
Subtopic: Group 15 - Preparation, Properties & Uses |
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| Statement-I: | E2O5 is less acidic than E2O3 (element E belongs to 15th group). |
| Statement-II: | E2O3 acidic strength decreases down the group (element E belongs to 15th group). |
| 1. | Both Statement-I & Statement-II are true. |
| 2. | Both Statement-I & Statement-II are false. |
| 3. | Statement-I is true while Statement-II is false. |
| 4. | Statement-I is false while Statement-II is true. |
Subtopic: Group 15 - Preparation, Properties & Uses |
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Subtopic: Group 15 - Preparation, Properties & Uses |
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Consider the following reaction,
\(\begin{aligned} &\mathrm{PCl}_{5}+\mathrm{H}_{2} \mathrm{O} \longrightarrow \mathrm{A}+\mathrm{HCl} \\ &\mathrm{A}+\mathrm{H}_{2} \mathrm{O} \longrightarrow \mathrm{B}+\mathrm{HCl} \end{aligned}\)
then the maximum numbers of ionizable hydrogen in B are:
1. 2
2. 0
3. 3
4. 1
\(\begin{aligned} &\mathrm{PCl}_{5}+\mathrm{H}_{2} \mathrm{O} \longrightarrow \mathrm{A}+\mathrm{HCl} \\ &\mathrm{A}+\mathrm{H}_{2} \mathrm{O} \longrightarrow \mathrm{B}+\mathrm{HCl} \end{aligned}\)
then the maximum numbers of ionizable hydrogen in B are:
1. 2
2. 0
3. 3
4. 1
Subtopic: Group 16 - Preparation, Properties & Uses |
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Lead nitrate decomposes on heating as:
\(\mathrm{Pb}\left(\mathrm{NO}_{3}\right)_{2} \stackrel{\Delta}{\longrightarrow} \mathrm{A}+\mathrm{PbO}+\mathrm{O}_{2} \)
'A' on dimerization gives 'B', then the number of bridging oxygen atom(s) in 'B' is:
1. 1
2. 0
3. 2
4. 3
\(\mathrm{Pb}\left(\mathrm{NO}_{3}\right)_{2} \stackrel{\Delta}{\longrightarrow} \mathrm{A}+\mathrm{PbO}+\mathrm{O}_{2} \)
'A' on dimerization gives 'B', then the number of bridging oxygen atom(s) in 'B' is:
1. 1
2. 0
3. 2
4. 3
Subtopic: Group 15 - Preparation, Properties & Uses |
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