premium feature crown icon
Unlock IMPORTANT QUESTION
This question was bookmarked by 5 NEET 2025 toppers during their NEETprep journey. Get Target Batch to see this question.
✨ Perfect for quick revision & accuracy boost
Buy Target Batch
Access all premium questions instantly

Calculate the acceleration of the block and trolly system shown in the figure. The coefficient of kinetic friction between the trolly and the surface is \(0.05.\) 
\(g=10~\text{m/s}^2,\) the mass of the string is negligible and no other friction exists)

1. \( 1.25~\text{m/s}^2\) 2. \( 1.50~\text{m/s}^2\)
3. \(1.66~\text{m/s}^2\) 4. \( 1.00~\text{m/s}^2\)
Subtopic:  Friction |
 67%
Level 2: 60%+
NEET - 2020
Hints
Links

premium feature crown icon
Unlock IMPORTANT QUESTION
This question was bookmarked by 5 NEET 2025 toppers during their NEETprep journey. Get Target Batch to see this question.
✨ Perfect for quick revision & accuracy boost
Buy Target Batch
Access all premium questions instantly

See the figure given below, a mass of \(4~\text{kg}\) rests on a horizontal plane. The plane is gradually inclined until at an angle \(\theta=15^\circ\) with the horizontal, the mass just begins to slide. What is the coefficient of static friction between the block and the surface?

 
1. \(0.27\)
2. \(0.53\)
3. \(0.23\)
4. \(0.25\)

Subtopic:  Friction |
 62%
Level 2: 60%+
Hints
Links

premium feature crown icon
Unlock IMPORTANT QUESTION
This question was bookmarked by 5 NEET 2025 toppers during their NEETprep journey. Get Target Batch to see this question.
✨ Perfect for quick revision & accuracy boost
Buy Target Batch
Access all premium questions instantly
Determine the maximum acceleration of the train in which a box lying on its floor will remain stationary, given that the coefficient of static friction between the box and the train’s floor is \(0.15.\)
1. \(0\)
2. \(0.5~\text{m/s}^2\)
3. \(2.5~\text{m/s}^2\)
4. \(1.5~\text{m/s}^2\)
Subtopic:  Friction |
 80%
Level 1: 80%+
Hints
Links

advertisementadvertisement