The mass of CO2 produced by heating 20 g of 20% pure limestone as per the given below equation is: \(\left[\mathrm{CaCO}_3 \stackrel{1200 \mathrm{~K}}{\longrightarrow} \mathrm{CaO}+\mathrm{CO}_2\right] \)
1.
1.32 g
2.
1.12 g
3.
1.76 g
4.
2.64 g
Subtopic: Equation Based Problem |
72%
From NCERT
NEET - 2023
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Calculate the mass of 95% pure CaCO3 that will be required to neutralize 50 mL of 0.5 M HCl solution according to the following reaction.
CaCO3(s) + 2HCl(aq) → CaCl2(aq) + CO2(g) + 2H2O(l)
[Calculate up to the second place of decimal point]
1.
9.50 g
2.
1.25 g
3.
1.32 g
4.
3.65 g
Subtopic: Equation Based Problem |
52%
From NCERT
NEET - 2022
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NEET 2023 - Target Batch - Aryan Raj Singh
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NEET 2023 - Target Batch - Aryan Raj Singh
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