Polaroid glass is used in sun glasses because:
1. it reduces the light intensity to half on account of polarisation
2. it is fashionable
3. it has good colour
4. it is cheaper
Subtopic:  Polarization of Light |
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Two polaroids are placed at an angle of \(45^\circ\) to each other. If an unpolarized light of intensity \(I_0\) falls as one polaroid, then the intensity of light leaves the second polaroid is:
1. \(\dfrac{I_0}{2}\) 2. \(\dfrac{I_0}{2 \sqrt{2}}\)
3. \(\dfrac{I_0}{4} \) 4. \( \dfrac{I_0}{8}\)
Subtopic:  Polarization of Light |
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Unpolarised light of intensity \(X\) is incident on a polarising sheet. A second polaroid whose pass-axis makes an angle \(30^\circ\) with the pass-axis of the first polaroid is kept behind it. The intensity of the light that gets transmitted after the second polaroid is:
1. \(X\) 2. \(\dfrac{3X}{8}\)
3. \(\dfrac{X}{4}\) 4. \(\dfrac{X}{2}\)
Subtopic:  Polarization of Light |
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An unpolarised light beam of intensity \(2I_0\) is passed through a polaroid \(P\) and then through another polaroid \(Q\) which is oriented in such a way that its passing axis makes an angle of \(30^{\circ}\) relative to that of \(P\). The intensity of the emergent light is:
1. \(\dfrac{I_0}{4} \)
2. \(\dfrac{I_0}{2} \)
3. \(\dfrac{3 I_0}{4} \)
4. \(\dfrac{3 I_0}{2}\)
Subtopic:  Polarization of Light |
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Level 1: 80%+
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Two polarisers \(P_1\) and \(P_2\) are placed such that the angle between their transmission axis is \(45^{\circ}\). Ordinary light is passed through \(P_1,\) \(I_1\) intensity is observed and when this light is passed through \(P_2,\) \(I_2\) intensity is observed. The ratio of \(\dfrac{I_1}{I_2}\) is:
1. \(\dfrac{4}{3}\) 2. \(\dfrac{3}{4}\)
3. \(2\) 4. \(\dfrac{1}{2}\)
Subtopic:  Polarization of Light |
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Level 2: 60%+
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A beam of unpolarised light of intensity \(I_0\) is passed through a polaroid \(A,\) through another polaroid \(B,\) oriented at \(60^\circ\) and finally through another polaroid \(C,\) oriented at \(45^\circ\) relative to \(B\) as shown in the figure. The intensity of the emergent light is:
1. \(\dfrac{{I}_0}{16}\) 2. \(\dfrac{{I}_0}4\)
3. \(\dfrac{{I}_0}2\) 4. \(\dfrac{{I}_0}{32}\)
Subtopic:  Polarization of Light |
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Level 2: 60%+
NEET - 2024
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Which of the following phenomena cannot be explained using the wave theory of light?
(A) Reflection
(B) Diffraction
(C) Photoelectric effect
(D) Interference
(E) Polarisation

Choose the correct option from the given ones:
1. (E) only 2. (A), (C) only
3. (B), (D) only 4. (C) only
Subtopic:  Polarization of Light |
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Given below are two statements: 
Assertion (A): Radio waves can be polarised.
Reason (R): Sound waves in the air are longitudinal in nature.
 
1. Both (A) and (R) are True and (R) is the correct explanation of (A).
2. Both (A) and (R) are True but (R) is not the correct explanation of (A).
3. (A) is True but (R) is False.
4. Both (A) and (R) are False.
Subtopic:  Polarization of Light |
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The Brewster's angle for an interface should be:
1. \(30^{\circ}<i_b<45^{\circ}\)
2. \(45^{\circ}<i_b<90^{\circ}\)
3. \(i_b=90^{\circ}\)
4. \(0^{\circ}<i_b<30^{\circ}\)

Subtopic:  Polarization of Light |
 75%
Level 2: 60%+
NEET - 2020
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