The effective capacity of the network between terminals \(\mathrm{A}\) and \(\mathrm{B}\) is:
1. \(6~\mu\text{F}~\)
2. \(20~\mu\text{F} ~\)
3. \(3~\mu\text{F}~\)
4. \(10~\mu\text{F}\)
Three uncharged capacitors of capacities \(C_1, C_2~\text{and}~C_3~~\) are connected to one another as shown in the figure.
If points \(\mathrm{A}\), \(\mathrm{B}\), and \(\mathrm{D}\), are at potential \(V_1, V_2 ~\text{and}~V_3\) then the potential at \(\mathrm{O}\) will be:
1. \(\frac{V_1C_1+V_2C_2+V_3C_3}{C_1+C_2+C_3}\)
2. \(\frac{V_1+V_2+V_3}{C_1+C_2+C_3}\)
3. \(\frac{V_1(V_2+V_3)}{C_1(C_2+C_3)}\)
4. \(\frac{V_1V_2V_3}{C_1C_2C_3}\)
Three capacitors each of capacity \(4\) µF are to be connected in such a way that the effective capacitance is \(6\) µF. This can be done by:
1. | connecting all of them in a series. |
2. | connecting them in parallel. |
3. | connecting two in series and one in parallel. |
4. | connecting two in parallel and one in series. |
Three capacitors of capacitances 3 μF, 9 μF and 18 μF are connected once in series and another time in parallel. The ratio of equivalent capacitance in the two cases will be:
1. 1 : 15
2. 15 : 1
3. 1 : 1
4. 1 : 3
Two capacitors of capacitance \(6~\mu\text{F}\) and \(3~\mu\text{F}\) are connected in series with battery of \(30~\text{V}\). The charge on \(3~\mu\text{F}\) capacitor at a steady state is:
1. \( 3 ~\mu\text{C}\)
2. \( 1.5 ~\mu\text{C}\)
3. \( 60~\mu\text{C}\)
4. \( 900~\mu\text{C}\)
The equivalent capacitance across \(A\) and \(B\) in the given figure is:
1. \( \frac{3}{2}C\)
2. \(C\)
3. \( \frac{2}{3}C\)
4. \( \frac{5}{3}C\)
Three capacitors each of capacitance C and of breakdown voltage V are joined in series. The capacitance and breakdown voltage of the combination will be:
1.
2.
3.
4.
The equivalent capacitance of the following arrangement is:
1.
2.
3.
4.
The equivalent capacitance between points a and b in the network shown below is:
1. 5C
2. 4C
3. 3C
4. 2C
A capacitor of capacity C1 is charged up to V volt and then connected to an uncharged capacitor C2. Then final P.D. across each will be:
1.
2.
3.
4.