- 1(current)
Q. No.A cell has emf of \(2.2~\text V\) and its internal resistance is \(0.1~\Omega.\) What is the current in the circuit, if the cell is connected across a resistance of \(1~\Omega?\)
1. \(1~\text A \)
2. \(1.5~\text A \)
3. \(2.0~\text A \)
4. \(2.5~\text A \)
1. \(1~\text A \)
2. \(1.5~\text A \)
3. \(2.0~\text A \)
4. \(2.5~\text A \)
Subtopic: Grouping of Cells |
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Level 1: 80%+
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The maximum power that a combination of two cells of EMF \(E_1\) & \(E_2\) \((E_1>E_2)\) can transfer to an external resistance is \(2~\text{W},\) when they are connected in series. When the EMF's are connected in opposite sense, but in series, this power is \(0.5~\text{W}.\) The ratio of the EMF's is, \((E_1/E_2)\)
1. \(4\)
2. \(3\)
3. \(2\)
4. \(1\)
1. \(4\)
2. \(3\)
3. \(2\)
4. \(1\)
Subtopic: Grouping of Cells |
84%
Level 1: 80%+
Hints
The combination of two identical cells, whether connected in series or parallel combination provides the same current through an external resistance of \(2~\Omega\). The value of the internal resistance of each cell is:
1. \(2~\Omega\)
2. \(4~\Omega\)
3. \(6~\Omega\)
4. \(8~\Omega\)
1. \(2~\Omega\)
2. \(4~\Omega\)
3. \(6~\Omega\)
4. \(8~\Omega\)
Subtopic: Grouping of Cells |
82%
Level 1: 80%+
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The figure shows a circuit with two cells connected in opposition. One cell has an EMF of \(6~\text{V}\) and an internal resistance of \({2}~\Omega,\) while the other cell has an EMF of \(4~\text{V}\) and an internal resistance of \({8}~\Omega.\) The potential difference across the terminals \(X\) and \(Y\) is:
| 1. | \(5.4\) V | 2. | \(5.6\) V |
| 3. | \(5.8\) V | 4. | \(6.0\) V |
Subtopic: Grouping of Cells |
82%
Level 1: 80%+
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- 1(current)
Q. No.
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