The ratio of escape velocity at the Earth \((v_e)\) to the escape velocity at a planet \((v_p)\) whose radius and mean density are twice that of the Earth is:
1. \(1:2\sqrt{2}\)
2. \(1:4\)
3. \(1:\sqrt{2}\)
4. \(1:2\)
Subtopic:  Escape velocity |
 73%
Level 2: 60%+
NEET - 2016
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