Light travels faster in the air than in glass. This is in accordance with:
1. | the wave theory of light. |
2. | the corpuscular theory of light. |
3. | neither \((1)\) nor \((2)\) |
4. | both \((1)\) and \((2)\) |
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In Young's double-slit experiment, the slit separation is doubled. This results in:
1. | An increase in fringe intensity |
2. | A decrease in fringe intensity |
3. | Halving of the fringe spacing |
4. | Doubling of the fringe spacing |
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In Young's double-slit experiment, the light emitted from the source has \(\lambda = 6.5\times 10^{-7}~\text{m}\) and the distance between the two slits is \(1~\text{mm}.\) The distance between the screen and slits is \(1~\text m.\) The distance between third dark and fifth bright fringe will be:
1. \(3.2~\text{mm}\)
2. \(1.63~\text{mm}\)
3. \(0.585~\text{mm}\)
4. \(2.31~\text{mm}\)
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In Young’s double slit experiment, the slits are \(2~\text{mm}\) apart and are illuminated by photons of two wavelengths \(\lambda_1 = 12000~\mathring{A}\) and \(\lambda_2 = 10000~\mathring{A}\). At what minimum distance from the common central bright fringe on the screen, \(2~\text{m}\) from the slit, will a bright fringe from one interference pattern coincide with a bright fringe from the other?
1. \(6~\text{mm}\)
2. \(4~\text{mm}\)
3. \(3~\text{mm}\)
4. \(8~\text{mm}\)
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A beam of light of \(\lambda = 600~\text{nm}\) from a distant source falls on a single slit \(1~\text{mm}\) wide and the resulting diffraction pattern is observed on a screen \(2~\text{m}\) away. The distance between the first dark fringes on either side of the central bright fringe is:
1. \(1.2~\text{cm}\)
2. \(1.2~\text{mm}\)
3. \(2.4~\text{cm}\)
4. \(2.4~\text{mm}\)
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1. | the intensities of individual sources are \(5\) and \(4\) units respectively. |
2. | the intensities of individual sources are \(4\) and \(1\) unit respectively. |
3. | the ratio of their amplitudes is \(3\). |
4. | the ratio of their amplitudes is \(6\). |
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Two superposing waves are represented by the following equations: \(y_1=5 \sin 2 \pi(10{t}-0.1 {x}), {y}_2=10 \sin 2 \pi(10{t}-0.1 {x}).\)
The ratio of intensities \(\dfrac{I_{max}}{I_{min}}\) will be:
1. \(1\)
2. \(9\)
3. \(4\)
4. \(16\)
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Two polaroids are kept crossed to each other. Now one of them is rotated through an angle of \(45^{\circ}\)
1. \(15\%\)
2. \(25\%\)
3. \(50\%\)
4. \(60\%\)
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