An electric dipole of moment \(p\) is placed in an electric field of intensity \(E\). The dipole acquires a position such that the axis of the dipole makes an angle \(\theta\) with the direction of the field. Assuming that the potential energy of the dipole to be zero when \(\theta = 90^{\circ},\) the torque and the potential energy of the dipole will respectively be:

1. \(p E \sin \theta,-p E \cos \theta\) 2. \(p E \sin \theta,-2 p E \cos \theta\)
3. \(p E \sin \theta, 2 p E \cos \theta\) 4. \(p E \cos \theta,-p E \sin \theta\)
Subtopic:  Energy of Dipole in an External Field |
 82%
From NCERT
NEET - 2012

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An electric dipole of moment \(\vec {p} \) is lying along a uniform electric field \(\vec{E}\). The work done in rotating the dipole by \(90^{\circ}\) is:
1. \(\sqrt{2}pE\)
2. \(\frac{pE}{2}\)
3. \(2pE\)
4. \(pE\)

Subtopic:  Energy of Dipole in an External Field |
 82%
From NCERT
AIPMT - 2006

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An electric dipole has the magnitude of its charges as q and its dipole moment is p. It is placed in a uniform electric field E. If its dipole moment is along the direction of the field, the force on it and its potential energy are respectively:

1. q.E and p.E
2. zero and minimum
3. q.E and maximum
4. 2q.E and minimum 

Subtopic:  Energy of Dipole in an External Field |
 77%
From NCERT
AIPMT - 2004

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A short electric dipole has a dipole moment of \(16 \times 10^{-9} ~\text{C-}\text{m}\). The electric potential due to the dipole at a point at a distance of \(0.6~\text{m}\) from the centre of the dipole situated on a line making an angle of \(60^{\circ}\) with the dipole axis is: \(\left( \frac{1}{4\pi \varepsilon_0}= 9\times 10^{9}~\text{N-m}^2/\text{C}^2\right)\)
1. \(200~\text{V}\)
2. \(400~\text{V}\)
3. zero
4. \(50~\text{V}\)

Subtopic:  Energy of Dipole in an External Field |
 66%
From NCERT
NEET - 2020

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An electric dipole with dipole moment p=3i^+4j^×10-30 C-is placed in an electric field E=4000i^N/C. An external agent turns the dipole slowly until its electric dipole moment becomes -4i^+3j^×10-30 C-m. The work done by the external agent is equal to:

1. 4 × 10–28  J 

2. –4 × 10–28  J

3. 2.8 × 10–26  J 

4. –2.8 × 10–26  J

Subtopic:  Energy of Dipole in an External Field |
From NCERT

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