- 1(current)
Q. No.Which one of the following gives the value of the magnetic field according to Biot-Savart’s law?
| 1. | \(\dfrac{{i} \Delta {l} \sin (\theta)}{{r}^2} \) | 2. | \(\dfrac{\mu_0}{4 \pi} \dfrac{i \Delta {l} \sin (\theta)}{r} \) |
| 3. | \(\dfrac{\mu_0}{4 \pi} \dfrac{{i} \Delta{l} \sin (\theta)}{{r}^2} \) | 4. | \(\dfrac{\mu_0}{4 \pi} {i} \Delta {l} \sin (\theta)\) |
To unlock all the explanations of this course, you need to be enrolled.
To unlock all the explanations of this course, you need to be enrolled.
| 1. | \(0^{\circ}\) | 2. | \(90^{\circ}\) |
| 3. | \(180^{\circ}\) | 4. | \(45^{\circ}\) |
To unlock all the explanations of this course, you need to be enrolled.
To unlock all the explanations of this course, you need to be enrolled.
An element \(\Delta l=\Delta x \hat{i}\) is placed at the origin and carries a large current of \(I=10~\text A\) (as shown in the figure). What is the magnetic field on the \(y\text-\)axis at a distance of \(0.5~\text m?\)
\((\text{Given}~\Delta x=1~\text{cm})\)
| 1. | \(6\times 10^{-8}~\text{T}\) | 2. | \(4\times 10^{-8}~\text{T}\) |
| 3. | \(5\times 10^{-8}~\text{T}\) | 4. | \(5.4\times 10^{-8}~\text{T}\) |
To unlock all the explanations of this course, you need to be enrolled.
To unlock all the explanations of this course, you need to be enrolled.
| 1. | \(0\) | 2. | \(1.2\times 10^{-4}~\text{T}\) |
| 3. | \(2.1\times 10^{-4}~\text{T}\) | 4. | None of these |
To unlock all the explanations of this course, you need to be enrolled.
To unlock all the explanations of this course, you need to be enrolled.
Which one of the following expressions represents Biot-Savart's law? Symbols have their usual meanings.
| 1. | \(\overrightarrow{d B}=\frac{\mu_0 \mathrm{I}(\overrightarrow{d l} \times \hat r)}{4 \pi|\overrightarrow{\mathrm{r}}|^3}\\ \) | 2. | \(\overrightarrow{d B}=\frac{\mu_0 \mathrm{I}(\overrightarrow{d l} \times \hat r)}{4 \pi|\overrightarrow{\mathrm{r}}|^2} \) |
| 3. | \(\overrightarrow{d B}=\frac{\mu_0 \mathrm{I}(\overrightarrow{d l} \times \vec{r})}{4 \pi|\vec{r}|^3} \) | 4. | \(\overrightarrow{d B}=\frac{\mu_0 \mathrm{I}(\overrightarrow{d l} \cdot \vec{r})}{4 \pi|\overrightarrow{\mathrm{r}}|^3}\) |
To unlock all the explanations of this course, you need to be enrolled.
To unlock all the explanations of this course, you need to be enrolled.
- 1(current)
Q. No.
© 2025 GoodEd Technologies Pvt. Ltd.