The IUPAC name of the above compound is:
1. 1-Phenylpropan-2-ol
2. 2-Phenylpropan-2-ol
3. 1-Phenylpropan-1-ol
4. 2-Phenylpropan-1-ol
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The IUPAC name of the below compound is:
1. 3,4-Dimethylhexane –1,3,5-triol
2. 3,5-Dimethylhexane –1,1,5-triol
3. 3,5-Dimethylhexane –1,3,5-triol
4. 3,1-Dimethylhexane –1,3,5-triol
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"A" in the reaction below is:
1. | Chlorobenzene | 2. | 1,2-Dichlorobenzene |
3. | 1,3-dichlorobenzene | 4. | None of these |
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Match the following:
List I | List II | ||
i. | O2N-C6H5-OCH3 (p) | a. | 4-Ethoxy-1,1-dimethylcyclohexane |
ii. | C2H5OCH2-CH(CH3)2 | b. | 1-Chloro-2-methoxyethane |
iii. | CH3OCH2CH2Cl | c. | 1-Ethoxy-2-methylpropane |
iv. | |
d. | 1-Methoxy-4-nitrobenzene |
i | ii | iii | iv | |
1. | d | c | b | a |
2. | c | d | b | a |
3. | a | c | b | d |
4. | b | c | d | a |
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Preparation of ethers by 2 or 3-degree alcohols in an acidic medium is not a suitable method because:
1. | In case of secondary or tertiary alcohols, ketone is obtained as a product. |
2. | In case of secondary or tertiary alcohols, aldehyde is obtained as a product. |
3. | In case of secondary or tertiary alcohols, alkene is obtained as a product. |
4. | In case of primary alcohols, alkene is obtained as a product. |
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Propanol has a higher boiling point than that of butane because -
1. Butane undergoes intermolecular ionic bonding
2. Propanol undergoes intermolecular H-bonding
3. Propanol undergoes intramolecular hydrogen bonding
4. Butane undergoes intermolecular H-bonding
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Identify Z in the following reaction:
\(CH_3CH_2CH=CH_2 \xrightarrow[H_2O,\ H_2O_2,\ OH^-]{B_2H_6} Z \)
1. | \(CH_3CH_2CH_2CH_2OH\) | 2. | \(CH_3CH_2 \ C \ HCH_3 \\~~~~~~~~~~~~~~~~~~| \\~~~~~~~~~~~~~~~~OH\) |
3. | \(CH_3CH_2CH_2CHO \) | 4. | \(CH_3CH_2CH_2CH_3 \) |
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The most acidic compound among the following is:
1. | |
2. | |
3. | |
4. |
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Upon dehydration, the below mentioned compound will not give:
1. | 2. | |
|
3. | |
4. | |
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An appropriate set of reactants for the preparation of 1-methoxy-4-nitrobenzene is/are :
1. | |
2. | |
3. | |
4. |
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