The temperature of a body falls from \(50^{\circ}\mathrm{C}\) to \(40^{\circ}\mathrm{C}\) in 10 minutes. If the temperature of the surroundings is \(20^{\circ}\mathrm{C}\), then the temperature of the body after another 10 minutes will be:
1. \(36.6^{\circ}\mathrm{C}\)          
2. \(33.3^{\circ}\mathrm{C}\)
3. \(35^{\circ}\mathrm{C}\)             
4. \(30^{\circ}\mathrm{C}\)

Subtopic:  Newton's Law of Cooling |
 78%
From NCERT

To unlock all the explanations of this course, you need to be enrolled.

Hints
Links

To unlock all the explanations of this course, you need to be enrolled.


A pan filled with hot food cools in 2 minutes from \(94^{\circ}\mathrm{C}\) to \(86^{\circ}\mathrm{C}\) when the room temperature is \(20^{\circ}\mathrm{C}\). How long will it take to cool from \(71^{\circ}\mathrm{C}\) to \(69^{\circ}\mathrm{C}\)?

1. 50 sec 2. 52 sec
3. 42 sec 4. 48 sec

Subtopic:  Newton's Law of Cooling |
 78%
From NCERT

To unlock all the explanations of this course, you need to be enrolled.

Hints
Links

To unlock all the explanations of this course, you need to be enrolled.


A block of metal is heated to a temperature much higher than the room temperature and allowed to cool in a room free from air currents. Which of the following curves correctly represents the rate of cooling?

1. 2.
3. 4.
Subtopic:  Newton's Law of Cooling |
 78%
From NCERT

To unlock all the explanations of this course, you need to be enrolled.

Hints
Links

To unlock all the explanations of this course, you need to be enrolled.


advertisementadvertisement

A certain quantity of water cools from \(70^{\circ}\mathrm{C}\) to \(60^{\circ}\mathrm{C}\) in the first 5 minutes and to \(54^{\circ}\mathrm{C}\) in the next 5 minutes. 
The temperature of the surroundings will be: 

1. \(45^{\circ}\mathrm{C}\) 2. \(20^{\circ}\mathrm{C}\)
3. \(42^{\circ}\mathrm{C}\) 4. \(10^{\circ}\mathrm{C}\)
Subtopic:  Newton's Law of Cooling |
 76%
From NCERT
NEET - 2014

To unlock all the explanations of this course, you need to be enrolled.

Hints
Links

To unlock all the explanations of this course, you need to be enrolled.


Hot coffee in a mug cools from \(90^{\circ}\mathrm{C}\) to \(70^{\circ}\mathrm{C}\) in 4.8 minutes. The room temperature is \(20^{\circ}\mathrm{C}\). Applying Newton's law of cooling, the time needed to cool it further by \(10^{\circ}\mathrm{C}\) should be nearly:

1. 4.2 minute 2. 3.8 minute
3. 3.2 minute 4. 2.4 minute
Subtopic:  Newton's Law of Cooling |
 69%
From NCERT

To unlock all the explanations of this course, you need to be enrolled.

Hints
Links

To unlock all the explanations of this course, you need to be enrolled.