- 1(current)
Q. No.The empirical formula and molecular mass of a compound are and 180 g, respectively. The molecular formula of the compound is -
| 1. C9H18O9 | 2. CH2O |
| 3. C6H12O6 | 4. C2H4O2 |
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The molar mass of naturally occurring Argon isotopes is:
| Isotope | Isotopic molar mass | Abundance |
| 36-Ar | 35.96755 g mol–1 | 0.337% |
| 38-Ar | 37.96272 g mol–1 | 0.063% |
| 40-Ar | 39.9624 g mol–1 | 99.600% |
| 1. | 49.99947 g mol-1 | 2. | 39.99947 g mol-1 |
| 3. | 35.59947 g mol-1 | 4. | 45.59947 g mol-1 |
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On complete combustion, 44 g of a sample of a compound gives 88 g CO2 and 36 g of H2O. The molecular formula of the compound may be:
1.
2.
3.
4.
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An organic compound contains carbon, hydrogen, and oxygen. Its elemental analysis gave C, 38.71%, and H, 9.67%. The empirical formula of the compound would be:
| 1. | CH3O | 2. | CH2O |
| 3. | CHO | 4. | CH4O |
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- 1(current)
Q. No.
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