Q. No.Match the following:
| COLUMN I | COLUMN II |
| A. 88 g of CO2 | 1. 0.25 mol |
| B. 6.022×1023 molecules of H2O | 2. 2 mol |
| C. 5.6 L of O2 at STP | 3. 3 mol |
| D. 96 g of O2 | 4. 1 mol |
| A | B | C | D | |
| 1. | 2 | 4 | 1 | 3 |
| 2. | 1 | 2 | 3 | 4 |
| 3. | 1 | 4 | 3 | 2 |
| 4. | 4 | 1 | 3 | 2 |
To unlock all the explanations of this course, you need to be enrolled.
To unlock all the explanations of this course, you need to be enrolled.
To unlock all the explanations of this course, you need to be enrolled.
To unlock all the explanations of this course, you need to be enrolled.
Mark the species among the following that contains the highest number of atoms.
1. 4 g He
2. 46 g Na
3. 0.40 g Ca
4. 12 g He
To unlock all the explanations of this course, you need to be enrolled.
To unlock all the explanations of this course, you need to be enrolled.
| Assertion (A): | The number of molecules in 2 moles of NH3 is equal to the number of molecules in 4 moles of CH4. |
| Reason (R): | Both are chemically similar species. |
| 1. | Both (A) and (R) are true and (R) is the correct explanation of (A). |
| 2. | Both (A) and (R) are true but (R) is not the correct explanation of (A). |
| 3. | (A) is true but (R) is false. |
| 4. | Both (A) and (R) are false. |
To unlock all the explanations of this course, you need to be enrolled.
To unlock all the explanations of this course, you need to be enrolled.
The formula of an acid is The mass of 0.0242 moles of the acid is 1.657 g.
The atomic weight of X is:
| 1. | 35.5 | 2. | 28.1 |
| 3. | 128 | 4. | 19.0 |
To unlock all the explanations of this course, you need to be enrolled.
To unlock all the explanations of this course, you need to be enrolled.
The maximum number of molecules is present in which of the following?
1. 15 L of gas at STP
2. 5 L of gas at STP
3. 0.5 g of gas
4. 10 g of gas
To unlock all the explanations of this course, you need to be enrolled.
To unlock all the explanations of this course, you need to be enrolled.
An organic substance containing C, H, and O gave the following percentage composition :
C = 40.687%, H = 5.085% and O = 54.228%. The vapour density of this organic substance is 59.
The molecular formula of the compound will be:
1. C4H6O4
2. C4H6O2
3. C4H4O2
4. None of the above
To unlock all the explanations of this course, you need to be enrolled.
To unlock all the explanations of this course, you need to be enrolled.
An element X has the following isotopic composition,
200X : 90%, 199X : 8.0%, 202X : 2.0%
The weighted average atomic mass of the naturally occurring element X is closest to:
| 1. | 201 u | 2. | 202 u |
| 3. | 199 u | 4. | 200 u |
To unlock all the explanations of this course, you need to be enrolled.
To unlock all the explanations of this course, you need to be enrolled.
100 mL of solution having molarity of 1M and density 1.5 g/mL is mixed with 400 mL of water. The molarity of the solution will be: (final density is 1.25 g/mL )
| 1. | 4.4 M | 2. | 0.145 M |
| 3. | 0.52 M | 4. | 0.227 M |
To unlock all the explanations of this course, you need to be enrolled.
To unlock all the explanations of this course, you need to be enrolled.
© 2024 GoodEd Technologies Pvt. Ltd.