Select the correct option based on statements below:
Assertion (A): Dissolution of sugar in water proceeds via an increase in entropy.
Reason (R): Entropy decreases, when an egg is boiled hard.
  
1. Both (A) and (R) are true and (R) is the correct explanation of (A).
2. Both (A) and (R) are true but (R) is not the correct explanation of (A).
3. (A) is true but (R) is false.
4. Both (A) and (R) are false.

Subtopic:  Spontaneity & Entropy |
 62%
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Select the correct option based on statements below:
Assertion (A): Work done in an irreversible isothermal process at constant volume is zero.
Reason (R):  Work is assigned a negative sign during expansion and is assigned a positive sign during compression.
 
1. Both (A) and (R) are true and (R) is the correct explanation of (A).
2. Both (A) and (R) are true but (R) is not the correct explanation of (A).
3. (A) is true but (R) is false.
4. Both (A) and (R) are false.

Subtopic:  First Law of Thermodynamics |
 76%
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Select the correct option based on statements below:
Assertion (A):  Specific heat is an intensive property.
Reason (R):  Heat capacity is an extensive property.
 
1.  Both (A) and (R) are true and (R) is the correct explanation of (A).
2. Both (A) and (R) are true but (R) is not the correct explanation of (A).
3. (A) is true but (R) is false.
4. Both (A) and (R) are false.
Subtopic:  Classification of System, Extensive & Intensive Properties |
 71%
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12N2 (g) + 12O2 (g)  NO(g) ;
rH° = 90 kJ mol-1
NO(g) + 12O2(g)  NO2(g); 
rH° = -74 kJ mol-1

The thermodynamic stability of NO(g) based on the above data is:

1. Less than NO2(g) 

2. More than NO2(g)

3. Equal to NO2(g)

4. Insufficient data

Subtopic:  Enthalpy & Internal energy |
 71%
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For the graph given below, it can be concluded that work done during the process shown will be-

1. Zero 2. Negative
3. Positive 4. Cannot be determined
Subtopic:  First Law of Thermodynamics |
 65%
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Consider the following diagram for a reaction AC


      

The nature of the reaction is-

1. Exothermic

2. Endothermic

3. Reaction at equilibrium

4. None of the above

Subtopic:  Enthalpy & Internal energy |
 81%
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Consider the following diagram for a reaction AC:

The nature of the reaction is-

1. Exothermic 2. Endothermic
3. Reaction at equilibrium 4. None of the above
Subtopic:  Enthalpy & Internal energy |
 81%
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The equilibrium constant for a reaction is 10. The value of G° will be:

(R = 8.314 J K-1 mol-1 ; T = 300 K)

1. -5.74 kJ mol-1
2. - 5.74 J mol-1
3. + 4.57 kJ mol-1
4. -57.4 kJ mol-1

Subtopic:  Gibbs Energy Change |
 73%
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The standard enthalpy of the formation of CH3OH(l)  from the following data is:

\(\small{\mathrm{CH}_3 \mathrm{OH}_{(l)}+\frac{3}{2} \mathrm{O}_2(\mathrm{g}) \rightarrow \mathrm{CO}_2(\mathrm{g})+2 \mathrm{H}_2 \mathrm{O}_{(l)} \text {; }}\)
\( \Delta_{\mathrm{r}} \mathrm{H}^{\circ}=-726 \mathrm{~kJ} \mathrm{~mol}{ }^{-1}\)
\(\small{\mathrm{C}(\mathrm{s})+\mathrm{O}_2(\mathrm{g}) \rightarrow \mathrm{CO}_2(\mathrm{g}) \text {; } }\)
\(\Delta_{\mathrm{c}} \mathrm{H}^{\circ}=-393 \mathrm{~kJ} \mathrm{~mol}{ }^{-1}\)
\(\small{\mathrm{H}_{2(\mathrm{g})}+\frac{1}{2} \mathrm{O}_{2(\mathrm{g})} \rightarrow \mathrm{H}_2 \mathrm{O}_{(l)} \text {; } } \)
\(\Delta_{\mathrm{f}} \mathrm{H}^{\circ}=-286 \mathrm{~kJ} \mathrm{~mol}^{-1}\)
 
1. −239 kJ mol−1 2. +239 kJ mol−1
3. −47 kJ mol−1 4. +47 kJ mol−1
Subtopic:  Thermochemistry |
 61%
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 N2 + 3 H2  2NH3 ; rH° = -92.4 kJ mol-1. The standard enthalpy of formation of NH3 gas in the above reaction would be-

1. -92.4 J (mol)-1 2. -46.2 kJ (mol)-1
3. +46.2 J (mol)-1 4. +92.4 kJ (mol)-1


Subtopic:  Thermochemistry |
 81%
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