Q. No.An unsaturated hydrocarbon 'A' reacts with two molecules of H2 and upon reductive ozonolysis A gives butane-1,4-dial, ethanal, and propanone.
The IUPAC name of A is:
1. 2-Methylocta-2,6-diene
2. 2-Methylocta-1,5-diene
3. 3-Methylocta-2,6-diene
4. 2-Methylocta-1,6-diene
To unlock all the explanations of this course, you need to be enrolled.
To unlock all the explanations of this course, you need to be enrolled.
The mechanism & intermediate involved in the above reaction are:
1. Aromatic electrophilic substitution & carbocation
2. Aromatic Nucleophilic substitution & carbanion
3. Aromatic free radical substitution & Free radical
4. Carbene based substitution reaction & Carbene
The type of radicals that can be formed as intermediates during monochlorination of 2-methylpropane is-
1. Primary and tertiary radicals
2. Two types of primary radicals
3. Primary and secondary radicals
4. Two types of tertiary radical
To unlock all the explanations of this course, you need to be enrolled.
To unlock all the explanations of this course, you need to be enrolled.
The major product(s) in the below reaction is-
\(H_{3} C - CH = CH_{2} \xrightarrow[{\left(\right. Ph - CO - O \left.\right)_{2}}]{HBr} S\)
1. \(\underset{1 - Bromopropane}{H_{3} C - CH_{2} - CH_{2} Br}\)
2. \(\underset{2 - Bromopropane}{CH_{3} - \underset{Br}{\underset{\left|\right.}{CH}} - CH_{3}}\)
3. \(\underset{Propene}{CH_{3} - CH = CH_{2}}\)
4. None of the above
To unlock all the explanations of this course, you need to be enrolled.
To unlock all the explanations of this course, you need to be enrolled.
The products formed after ozonolysis of Pent-2-ene are:
1. Ethanal and Methanal
2. Ethanal and Propanal
3. Ethanal and Butanal
4. Ethanal and Ethanal
To unlock all the explanations of this course, you need to be enrolled.
To unlock all the explanations of this course, you need to be enrolled.
Among the two isomers given above, the reason behind higher boiling point of one isomer as compared to the order is :
1. Cis - less polar than trans
2. Trans - more polar than cis
3. Cis - more intermolecular forces
4. Trans - more dipole-dipole interactions
To unlock all the explanations of this course, you need to be enrolled.
To unlock all the explanations of this course, you need to be enrolled.
Decreasing order of acidic behavior of benzene, n-hexane, and ethyne is -
1. Hexane > Ethyne > Benzene
2. Benzene > Hexane > Ethyne
3. Ethyne > Benzene > Hexane
4. Benzene > Ethyne > Hexene
To unlock all the explanations of this course, you need to be enrolled.
To unlock all the explanations of this course, you need to be enrolled.
The reagent used in the above conversion is:
1. Cr2O3
2. Alc. KOH
3. Red hot Fe
4. NaNH2/liq.NH3
To unlock all the explanations of this course, you need to be enrolled.
To unlock all the explanations of this course, you need to be enrolled.
Out of the above alkenes, the ones that can give 2-methyl butane on hydrogenation are-
| 1. | a, b | 2. | b, c |
| 3. | a, c | 4. | a, b, c |
To unlock all the explanations of this course, you need to be enrolled.
To unlock all the explanations of this course, you need to be enrolled.
© 2024 GoodEd Technologies Pvt. Ltd.