A non-aromatic compound among the following compounds is:

1.		2.
3.		4.

A compound among the following that gives the maximum % of meta product on nitration

(using HNO₃/H₂SO₄) is :

1. Toluene

2. Aniline

3. Benzene

4. Isopropyl benzene

The action of AlCl₃ in Friedel Craft's reaction is:

1. To absorb HCl

2. To release HCl

3. To produce an eleçtrophile

4. To produce nucleophile

n-Butylbenzene on oxidation with hot alkaline KMnO₄ gives:

The compound among the following that undergoes bromination of its aromatic ring

(electrophilic aromatic substitution) at the fastest rate is-

1.		2.
3.		4.

Consider the following sequence of reactions.

${\mathrm{C}}_6{\mathrm{H}}_6$ $+$ ${\mathrm{CH}}_3\mathrm{CH}={\mathrm{CH}}_2\underset{\mathrm{heat}}{\overset{{\mathrm{H}}_3{\mathrm{PO}}_4}{\to }}\mathrm{A}\underset{2.{\mathrm{H}}_3{\mathrm{O}}^{+},}{\overset{}{\to }}$ $\mathrm{heat}1.{\mathrm{O}}_2,\mathrm{Heat}\mathrm{B}+\mathrm{C}$

The products (B) and (C) are respectively-

1. Benzaldehyde, and acetaldehyde

2. Benzoic acid, and acetic acid

3. Phenol, and propionaldehyde

4. Phenol, and acetone

In the above compound, Cl will liberate easily in the form of-

1. ${\mathrm{Cl}}^{\oplus }$

2. Cl^-

3. Cl

4. Cl²⁺

(A) C₈H₁₀ $\stackrel{{\mathrm{KMnO}}_4}{\to }$ (B)  C₈H₆O₄$\underset{\mathrm{Fe}}{\overset{{\mathrm{Br}}_2}{\to }}$  C₈H₅BrO₄  (C)  (one-product only)

The structure of A in the above-mentioned reaction is-

1.		2.
3.		4.

The product (B) in the above-mentioned reaction is-

1.		2.
3.		4.

Cyclopentadiene is much more acidic than cyclopentane, beacuse -

1. Cyclopentadiene has conjugated double bonds.

2. Cyclopentadiene has both sp² and sp³ hybridized carbon atoms.

3. Cyclopentadiene is a strain-free cyclic system.

4. Cyclopentadienyl anion ion, the conjugate base of cyclopentadiene, is an aromatic species and hence has higher stability.