The correct hybridization states of carbon atoms in the following compound are -
1. | C1= sp , C2= sp3 , C3= sp2 | 2. | C1= sp2 , C2= sp3 , C 3 = sp3 |
3. | C1= sp2 , C2= sp2 , C 3 = sp | 4. | C1= sp3 , C2= sp3 , C 3 = sp3 |
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The correct hybridization states of carbon atoms in C6H6 is/are:
1. sp2
2. sp
3. sp3
4. All of the above
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During estimation of nitrogen present in an organic compound, the ammonia evolved from 0.5 g of the compound in Kjeldahl’s estimation of nitrogen, neutralized 10 mL of 1 M H2SO4. The percentage of nitrogen in the compound is-
1. 46.0 %
2. 51.0%
3. 56.0%
4. 49.0%
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In sulphur estimation, 0.157 g of an organic compound gave 0.4813 g of barium sulphate. The percentage of sulphur in the compound is-
1. 39.10 %
2. 48.13 %
3. 42.10 %
4. 52. 43 %
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The correct hybridization states of carbon atoms marked as 1,2,3 in the following compound are -
1. | C1= sp , C2= sp3 , C3= sp2 | 2. | C1= sp2 , C2= sp3 , C3= sp3 |
3. | C1= sp3 , C2= sp2 , C3= sp2 | 4. | C1= sp3 , C2= sp3 , C3= sp3 |
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The correct hybridization states of carbon atoms in the above compound are -
1. | C1= sp , C2= sp3 | 2. | C1= sp2 , C2= sp |
3. | C1= sp3 , C2= sp | 4. | C1= sp , C2= sp2 |
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Chlorine atom can be classified as -
1. | Carbocation | 2. | Nucleophile |
3. | Electrophile | 4. | Carbanion |
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The number of σ and π bonds in the molecule are -
1. 2 = ( , 1= , and 1= π
2. 2 = ( , 2= , and 0= π
3. 2 = ( , 1= , and 1= π
4. 2 = ( , 1= , and 1= π
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The number of σ and π bonds in the molecule are-
1. 7 = ( , 11 = , and 0= π
2. 6 = ( , 12 = , and 0= π
3. 12 = ( , 6 = , and 1= π
4. 5 = ( , 13 = , and 1= π
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The number of σ and π bonds in the molecule are -
1. | 6 C – C sigma ( σ C - C ) bonds, 5 C–H sigma ( ( σ C - H ) bonds, and 3 C=C pi ( π C - C ) |
2. | 6 C – C sigma ( σ C - C ) bonds, 5 C–H sigma ( ( σ C - H ) bonds, and 2 C=C pi ( π C - C ) |
3. | 6 C – C sigma ( σ C - C ) bonds, 6 C–H sigma ( ( σ C - H ) bonds, and 3 C=C pi ( π C - C ) |
4. | 6 C – C sigma ( σ C - C ) bonds, 6 C–H sigma ( ( σ C - H ) bonds, and 2 C=C pi ( π C - C ) |
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