Match the element in Column I with that in Column II.

The period and group number of the element with Z =114 are:

Sodium generally does not show an oxidation state of +2, because of:

1. High first ionization potential.

2. High second ionization potential.

3. Large ionic radius.

4. High electronegativity.

The electronic configuration that represents the d-block element is: 

1. 1s² 2s² 2p⁶ 3s²3p⁶3d¹⁰ 4s²4p⁶

2. 1s² 2s² 2p⁶ 3s²3p⁶3d¹⁰ 4s²4p¹

3. 1s² 2s² 2p⁶ 3s²3p⁶3d¹⁰ 4s²

4. 1s² 2s² $2p^6$ 3s²3p⁶ 4s²

The general outer electronic configuration of s, p, d , and f-block elements respectively would be :

Consider the following electronic configuration of an element (P) :

$\left[\mathrm{Xe}\right]4{\mathrm{f}}^{14}5{\mathrm{d}}^{1}6{\mathrm{s}}^2$

The correct statement about element 'P' is :

1. It belongs to the 6th period and the 1st group.

2. It belongs to the 6th period and the 2nd group.

3. It belongs to the 6th period and the 3rd group.

4. None of the above.