- 1(current)
Q. No.1 g of a non-volatile non-electrolyte solute is dissolved in 100 g of two different solvents A and B whose ebullioscopic constants are in the ratio of 1 : 5. The ratio of the elevation in their boiling points, , is:
1. 5:1
2. 1:2
3. 10:1
4. 1:5
1. 4
2. 6
3. 10
4. 8
For an aqueous solution, freezing point is -0.186oC. Elevation of the boiling point of the same solution is:
(Given: Kf =1.86 K kg mol-1 and Kb = 0.512 K kg mol-1)
1. 0.186
2. 0.0512
3. 1.86
4. 5.12
1.00 g of a non-electrolyte solute dissolved in 50 g of benzene lowered the freezing point of benzene by 0.40 K. The freezing point depression constant of benzene is 5.12 K kg mol–1. The molar mass of the solute is:
| 1. | 245 g mol–1 |
2. | 256 g mol–1 |
| 3. | 264 g mol–1 |
4. | 274 g mol–1 |
| Statement I: | At 20 °C, the molality of KCl solution is 'X' m, and on decreasing temperature to -10 °C molality remains unchanged. |
| Statement II: | On changing temperature mass remains unchanged. |
| 1. | Both Statement I and Statement II are True. |
| 2. | Both Statement I and Statement II are False. |
| 3. | Statement I is True, and Statement II is False. |
| 4. | Statement I is False, and Statement II is True. |
Find the value of \(x\):
| 1. | Seven (7) | 2. | Three (3) |
| 3. | One (1) | 4. | Two (2) |
18 g of glucose (C₆H₁₂O₆) is dissolved in 1 kg of water. The boiling point of pure water at 1.013 bar is 100°C. The boiling point of the resulting solution is:
(Given: Kb for water is 0.52 K kg mol-1)
1. 383.202 K
2. 373.202 K
3. 363.202 K
4. 393.202 K
[Given : (\(K_b\)) for water is \(0.5~ K⋅kg/mol\), and the boiling point of pure water is \(100^∘C\)]
| 1. | \(105^\circ \text{C}\) | 2. | \(100.5^\circ \text{C}\) |
| 3. | \(273.5^\circ \text{C}\) | 4. | \(273.5^\circ \text{C}\) |
1. 0.06 K
2. 1.2 K
3. 0.12 K
4. 6.1 K
| 1. | 1.0 M NaOH | 2. | 1.0 M \(Na_2SO_4~~~~~~\) |
| 3. | 1.0 M \(NH_4NO_3~~~~\) | 4. | 1.0 M KNO3 |
- 1(current)
Q. No.
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