In Maxwell’s famous modification of Ampère’s law in electromagnetism, he introduced the concept of:
1. AC current 2. DC current
3. Displacement current 4. Reactance
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A parallel-plate capacitor of capacitance \(\dfrac{1}{2}\text{ F} \) is such that an instantaneous displacement current of \(i\) ampere flows between its plates. What is the corresponding rate of change of voltage \(\dfrac{dV}{dt}\)​ across the capacitor?
1. \(2i\) 2. \(\dfrac{i}{2}\)
3. \(\dfrac{1}{2i}\) 4. \(i\)
Subtopic:  Displacement Current |
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Displacement current exists:
1. when an electric field is changing in the circuit.
2. when an electric field is constant.
3. when an electric field is absent.
4. always exists independent of the electric field.
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A capacitor is connected across a battery which delivers a current of \(1~\text A\) at an instant in the capacitor. Displacement current through the capacitor at that instant is:
1. \(1~\text A\)
2. \(0 ~\text A\)
3. \(2~ \text A\)
4. \(0.5~{\text{A}}\)
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A parallel plate capacitor of capacitance \(20~\mu\text{F}\) is being charged by a voltage source whose potential is changing at the rate of \(3~\text{V/s}\). The conduction current through the connecting wires, and the displacement current through the plates of the capacitor, would be, respectively:
1. \(60~\mu\text{A}\), zero
2. zero, zero
3. zero, \(60~\mu\text{A}\)
4. \(60~\mu\text{A}, 60~\mu\text{A}\)

Subtopic:  Displacement Current |
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A displacement current of \(4.425~\mu\text A\) is developed in the space between the plates of a parallel plate capacitor when voltage is changing at a rate of \(10^{6}~\text{V/s}.\) The area of each plate of the capacitor is \(40~\text{cm}^2.\) The distance between each plate of the capacitor is \(x \times 10^{-3}~\text m.\) The value of \(x\) is:
(the permittivity of free space, \(\epsilon_0=8.85\times10^{-12}~\text{C}^2 \text{N}^{-1} \text{m}^{-2}\) )
1. \(2\)
2. \(4\)
3. \(6\)
4. \(8\)
Subtopic:  Displacement Current |
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The separation between the pate of a parallel plate capacitor is \(1\) mm is connected in an electric circuit if rate of change of voltage between the plate is \(10^8~~\text {V/s}\) and plate  area is \(30 ~\text {cm}^2\), then the value of displacement current between the plate will be:
1. \( 8.85 \mathrm{~mA} \)
2. \( 3.65 \mathrm{~mA} \)
3. \(2.65 \mathrm{~mA} \)
4. \( 9.57 \mathrm{~mA} \)
 
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Maxwell unified:

1. electricity and gravitation
2. electricity and magnetism
3. electromagnetism with weak nuclear forces
4. none of the above

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Correctly match the two lists.
List-I List-II
(A) Gauss's law (electrostatics) (P) \(\oint\vec {B}\cdot d\vec {A}=0\)
(B) Ampere's circuital law (Q) \(\oint\vec {B}\cdot d\vec {l}=\mu_0i_{\text{enclosed}}\)
(C) Gauss's law (magnetism) (R) \(\oint\vec E \cdot d \vec A=\dfrac{q_{_{\text{enclosed}}}}{\varepsilon_0}\)
(D) Faraday's law of induction (S) \( \varepsilon=-\dfrac{d\phi_{_B}}{dt}\)
 
1. \(\mathrm{(A)\rightarrow (R)},\mathrm{(B)\rightarrow (Q)},\mathrm{(C)\rightarrow (S)}, \mathrm{(D)\rightarrow (P)}\)
2. \(\mathrm{(A)\rightarrow (R)},\mathrm{(B)\rightarrow (Q)},\mathrm{(C)\rightarrow (P)}, \mathrm{(D)\rightarrow (S)}\)
3. \(\mathrm{(A)\rightarrow (R)},\mathrm{(B)\rightarrow (S)},\mathrm{(C)\rightarrow (Q)}, \mathrm{(D)\rightarrow (P)}\)
4. \(\mathrm{(A)\rightarrow (R)},\mathrm{(B)\rightarrow (S)},\mathrm{(C)\rightarrow (P)}, \mathrm{(D)\rightarrow (Q)}\)
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According to the modified Ampere's circuital law (Ampere-Maxwell Law), where \(i_c\)​ represents the conduction current and \(i_D\)​ represents the displacement current, the correct equation is:
1. \({\oint \vec B. d\vec{l}=\mu_0\left(i_c+\varepsilon_0\dfrac{{d}\phi_E}{dt}\right)} \)
2. \( { \oint \vec B.d\vec{l}~=~\mu_0~\varepsilon_0\dfrac{{d}\phi_E}{ dt}} \)
3. \( { \oint \vec B.d\vec{l}=\mu_0{i}} \)
4. \( { \oint \vec B. d\vec{l}=\mu_0\left(i_c\dfrac{d\phi_E}{dt}{+i_D}\right)}\)
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