Match the following:

Column-I Column-II
A.  88 g of CO2 1. 0.25 mol
B.  6.022×1023 molecules of H2O 2.  2 mol
C.  5.6 L of O2 at STP 3.  3 mol   
D.  96 g of O2 4. 1 mol
Codes:
A B C D
1. 2 4 1 3
2. 1 2 3 4
3. 1 4 3 2
4. 4 1 3 2
Subtopic:  Moles, Atoms & Electrons |
 91%
Level 1: 80%+

To unlock all the explanations of this course, you need to be enrolled.

Hints

To unlock all the explanations of this course, you need to be enrolled.


4.4 g of an unknown gas occupies 2.24 litres of volume at NTP. The gas may be: 

1. Carbon dioxide 2. Carbon monoxide
3. Oxygen 4. Sulphur dioxide
Subtopic:  Moles, Atoms & Electrons |
 87%
Level 1: 80%+

To unlock all the explanations of this course, you need to be enrolled.

Hints

To unlock all the explanations of this course, you need to be enrolled.


The number of  moles  present in 2.5 litres of 0.2 M  H2SO4 are:

1. 0.25

2. 0.5

3. 0.75

4. 0.2

Subtopic:  Moles, Atoms & Electrons |
 85%
Level 1: 80%+

To unlock all the explanations of this course, you need to be enrolled.

Hints
Links

To unlock all the explanations of this course, you need to be enrolled.


advertisementadvertisement

Mark the species among the following that contains the highest number of atoms:

1. 4 g He

2. 46 g Na

3. 0.40 g Ca

4. 12 g He

Subtopic:  Moles, Atoms & Electrons |
 84%
Level 1: 80%+

To unlock all the explanations of this course, you need to be enrolled.

Hints
Links

To unlock all the explanations of this course, you need to be enrolled.


The weight of 1x1023 molecules of CuSO4.5H2O is: 

1. 34.42 g

2. 41.42 g

3. 54.44 g

4. 68.94 g

Subtopic:  Moles, Atoms & Electrons |
 73%
Level 2: 60%+

To unlock all the explanations of this course, you need to be enrolled.

Hints

To unlock all the explanations of this course, you need to be enrolled.


Assertion (A): The number of molecules in 2 moles of NH3 is equal to the number of molecules in 4 moles of CH4.
Reason (R): Both are chemically similar species.
 
1. Both (A) and (R) are True and (R) is the correct explanation of (A).
2. Both (A) and (R) are True but (R) is not the correct explanation of (A).
3. (A) is True but (R) is False.
4. Both (A) and (R) are False.
Subtopic:  Moles, Atoms & Electrons |
 82%
Level 1: 80%+

To unlock all the explanations of this course, you need to be enrolled.

Hints

To unlock all the explanations of this course, you need to be enrolled.


advertisementadvertisement

The mass of carbon present in 0.5 mole of K4[Fe(CN)6] is:

1. 1.8 g 2. 18 g
3. 3.6 g 4. 36 g
Subtopic:  Moles, Atoms & Electrons |
 73%
Level 2: 60%+

To unlock all the explanations of this course, you need to be enrolled.

Hints

To unlock all the explanations of this course, you need to be enrolled.


The formula of an acid is HXO2. The mass of 0.0242 moles of the acid is 1.657 g.
The atomic weight of X is:

1. 35.5 2. 28.1
3. 128 4. 19.0
Subtopic:  Moles, Atoms & Electrons |
 73%
Level 2: 60%+

To unlock all the explanations of this course, you need to be enrolled.

Hints

To unlock all the explanations of this course, you need to be enrolled.


The amount of copper (in grams) that can be obtained from 100 g of copper sulphate (CuSO4is:

1. 54.00 2. 39.81
3. 63.50 4. 159.50
Subtopic:  Moles, Atoms & Electrons |
 71%
Level 2: 60%+

To unlock all the explanations of this course, you need to be enrolled.

Hints

To unlock all the explanations of this course, you need to be enrolled.


advertisementadvertisement

The iron content of haemoglobin is 0.33% by mass. Given that the molar mass of haemoglobin is 67,200 g mol⁻¹, determine the number of iron atoms present in each haemoglobin molecule.
(Atomic mass of Fe = 56)

1. 2
2. 3
3. 4
4. 5
Subtopic:  Moles, Atoms & Electrons |
 74%
Level 2: 60%+

To unlock all the explanations of this course, you need to be enrolled.

Hints
Links

To unlock all the explanations of this course, you need to be enrolled.