The hybridization and magnetic nature of ${\left[\mathrm{Mn}\right(\mathrm{CN}{)}_6]}^{-4}\text{\hspace{0.17em}and\hspace{0.17em}}{\left[\mathrm{Fe}\right(\mathrm{CN}{)}_6]}^{3-}$, respectively are:

1. $\begin{array}{l}{\mathrm{d}}^2{\mathrm{sp}}^3\end{array}$and diamagnetic

2. $\begin{array}{l}{\mathrm{sp}}^3{\mathrm{d}}^2\end{array}$and diamagnetic

3. ${\mathrm{d}}^2{\mathrm{sp}}^3$ and paramagnetic

4.  ${\mathrm{sp}}^3{\mathrm{d}}^2$ and paramagnetic

Simplified absorption spectra of three complexes ((i), (ii) and (iii)) of Mⁿ⁺ ion are provided below; their $\lambda$_max values are marked as A, B and C respectively. The correct match between the complexes and their $\lambda$_max values is:

	(i)	[M(NCS)6](-6+n)
	(ii)	[MF6](-6+n)
	(iii)	[M(NH3)6]n+

Options:

The d-electron configuration of [Ru(en)₃]Cl₂ and [Fe(H₂O)₆]Cl₂, respectively are :

1.  t_2g⁶ e_g⁰ and  t_2g⁴ e_g²
\(2.~ t_{2 g}^{4} e_{g}^{2}~ and ~t_{2 g}^{4} e_{g}^{2}\\ 3.~ t_{2 g}^{3} e_{g}^{3} ~and~ t_{2 g}^{4} e_{g}^{2}\\ 4.~ t_{2 g}^{4} e_{g}^{2} ~and~ t_{2 g}^{3} e_{g}^{3}\)

The values of the crystal field stabilization energies for a high spin d⁶ metal ion in octahedral and tetrahedral fields, respectively, are :

1. –0.4 ${∆}_0$ and –0.27 ${∆}_t$
2. –1.6 ${∆}_0$ and –0.4 ${∆}_t$
3. –0.4 ${∆}_0$ and –0.6 ${∆}_t$
4. –2.4 ${∆}_0$ and –0.6 ${∆}_t$

Considering that ${∆}_0>P$, the magnetic moment (in BM) of $[Ru{\left(H_{2}O\right)}_6{]}^{2+}$ would be:
1. 0
2. 4.9
3. 6.9
4. 3.5

For a ${\mathrm{d}}^4$ metal ion in an octahedral field, the correct electronic configuration is:

The correct statements among the following are:

1. (I), (II), and (III)
2. (II), and (III) only
3. (I), and (II) only
4. (I), and (III) only

The degenerate orbitals of \(\left[\right. C r \left(H_{2} O\right)_{6} ]^{3 +}\) are: 

1. \(d_{z^2}\) and \(d_{x z}\)

2. \(d_{y z}\) and \(d_{z^2}\)

3. \(d_{xz}\) and \(d_{y z}\)

4. \(d_{x^{2} - y^{2}}\) and \(d_{x y}\)

Which one of the following has a square planar geometry?
(At. Nos. Co = 27, Ni = 28, Fe = 26, Pt = 78)