The role of an electrolyte in the  preparation of H2 by electrolytic method is:

1. It lowers the availability of ions available in the process for the conduction of electricity.
2. It makes the ions available in the process for conduction of electricity.
3. It cools down the temperature.
4. None of the above

Subtopic:  Preparation & Properties |
 80%
Level 1: 80%+
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The products obtained on the completion of the following reactions (i) and (ii) respectively are :

i. C3H8(g) + 3H2O(g) \(\xrightarrow[Catalyst]{\Delta}\) A
ii. \(\mathrm{Zn}_{(s)}+\mathrm{NaOH}_{(\mathrm{aq})} \xrightarrow[]{Heat}\)B


1. A = CO, and H2 ; B = Na2ZnO2
2. A  = CO2 ; B = Na4ZnO4
3. A = CH3CH2CH2OH ; B=  ZnO
4. None of the above


 

 

Subtopic:  Preparation & Properties |
 77%
Level 2: 60%+
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The correct statement among the following regarding hydrogen is–

1. It can form a bond in +1 as well as –1 oxidation state

2. It is always collected at the cathode

3. It has a very low ionization potential

4. It has the same electronegativity as halogens

Subtopic:  Preparation & Properties |
 73%
Level 2: 60%+
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When substance A reacts with water, it produces a combustible gas B and a solution of substances 'C' in water. When another substance 'D' reacts with this solution of C, it produces the same gas 'B' on warming but 'D' can produce gas 'B' on reaction with dilute sulphuric acid at room temperature. 'A' imparts a deep golden yellow colour to a smokeless flame of a bunsen burner. A, B, C and D respectively are -

1. Na, H2, NaOH, Zn                              

2. K, H2, KOH, Al

3. Ca, H2, CaOH2, Sn                           

4. CaC2, C2H2, CaOH2, Fe

Subtopic:  Preparation & Properties |
 72%
Level 2: 60%+
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Dihydrogen gas cannot be prepared with-

1. Cu + HCl (dil.)

2. Fe + H2SO4

3. Mg + steam

4. Na + alcohol

Subtopic:  Preparation & Properties |
 56%
Level 3: 35%-60%
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