The set of a quantum number that represents degenerate orbitals is: 
 
a. \( \small{n=3, \ell=2, m=0, s=\frac{-1}{2} \,\& \ \,n=3, \ell=2, m=-1, s=\frac{+1}{2}}\)
b. \(\small{n=2, \ell=1, m=1 , \ s=\frac{-1}{2}\, \&\, \ n=3, \ell=1, m=1 \mathrm{~s}=\frac{+1}{2}}\)
c. \(\small{n=4, \ell=2, m=-1, s=\frac{1}{2}\, \&\, \ n=3, \ell=2, m=-1, s=\frac{1}{2}}\)

1. a 
2. b 
3. c 
4. a, b 
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Using the following statements, identify the correct set of statements:
(i). n (principal quantum number) can have values 1, 2, 3, 4, .......
(ii). The number of orbitals for a given value of l is (2l+1).
(iii). The value of spin quantum numbers is always \(\pm\frac12\).
(iv). For l=5, the total number of orbitals is 9.

1.  (i), (ii), (iii)
2.  (i), (ii), (iv)
3.  (i), (ii), (iii), (iv)
4.  (i), (iii), (iv)
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The plots of radial distribution functions for various orbitals of hydrogen atom against 'r' are given below:

a.

 

b.

 

c. 

d.

The correct plot for 3s orbital is:

1. (B)

2. (A)

3. (D)

4. (C)

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The graph between ψ2 and r (radial distance) is shown below. This represents:

1. 3s orbital 2. 2s orbital
3. 2p orbital 4. 1s orbital
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The correct set of four quantum numbers for the valence electrons of rubidium atom (Z = 37) is -

1. 5, 1, 0 + 12

2. 5, 1, 1 + 12

3. 5, 0, 1 +12

4. 5, 0, 0 + 12

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Consider the ground state of Cr atom (Z=24). The numbers of electrons with the azimuthal quantum numbers, l=1 and 2 are, respectively:

1. 12 and 4

2. 12 and 5

3. 16 and 4

4. 16 and 5

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How many sets of quantum numbers are possible?
 
n l m
(a). 2 2 1
(b). 3 2 -2
(c). 3 2 -1
(d). 2 1 -1

1. 0 
2. 1
3. 2 
4. 3 
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