With a ground state energy of –13.6 eV for a hydrogen atom, what would be the energy in the second excited state?
1. –6.8 eV
2. –3.4 eV
3. –1.51 eV
4. –4.53 eV
Consider the ground state of Cr atom (Z=24). The numbers of electrons with the azimuthal quantum numbers, l=1 and 2 are, respectively:
1. 12 and 4
2. 12 and 5
3. 16 and 4
4. 16 and 5
According to Bohr's theory, what is the angular momentum of an electron located in the fifth orbit?
1.
2.
3.
4.
n | l | m | |
(a). | 2 | 2 | 1 |
(b). | 3 | 2 | -2 |
(c). | 3 | 2 | -1 |
(d). | 2 | 1 | -1 |
Statement I: | |
Statement II: |
a. | \( \small{n=3, \ell=2, m=0, s=\frac{-1}{2} \,\& \ \,n=3, \ell=2, m=-1, s=\frac{+1}{2}}\) |
b. | \(\small{n=2, \ell=1, m=1 , \ s=\frac{-1}{2}\, \&\, \ n=3, \ell=1, m=1 \mathrm{~s}=\frac{+1}{2}}\) |
c. | \(\small{n=4, \ell=2, m=-1, s=\frac{1}{2}\, \&\, \ n=3, \ell=2, m=-1, s=\frac{1}{2}}\) |
(i). | n (principal quantum number) can have values 1, 2, 3, 4, ....... |
(ii). | The number of orbitals for a given value of l is (2l+1). |
(iii). | The value of spin quantum numbers is always \(\pm\frac12\). |
(iv). | For l=5, the total number of orbitals is 9. |