Value of m0 for  SrCl2 (strong electrolyte) in water at 25 °C from the data below is:

Conc. (mol/litre)  0.25 1
Ω-cmmol-1 260 250

1. 270 Ω-1 cm2 mol-1                                                     

2. 260 Ω-1 cm2 mol-1 

3. 250 Ω-1 cm2 mol-1                                                    

4. 255 Ω-1 cm2 mol-1 

Subtopic:   Kohlrausch Law & Cell Constant |
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During electrolysis of conc. H2SO4, perdisulphuric acid (H2S2O8), and O2 form in equimolar amount. The amount of H2 that will form simultaneously will be : 

1. Thrice that of O2 in moles.

2. Twice that of O2 in moles.

3. Equal to that of O2 in moles.

4. Half of that of O2 in moles.

Subtopic:  Faraday’s Law of Electrolysis |
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Consider the following Galvanic cell.

By what value the cell voltage change when concentration of ions in anodic and cathodic compartments both increased by a factor of 10 at 298 

1.  +0.0591

2.  -0.0591

3.  -0.1182

4.  0

 

Subtopic:  Electrode & Electrode Potential |
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Which characteristic of hydrogen makes it hazardous as a fuel?
1. High ignition with low combustion energy
2. High ignition with high combustion energy
3. Low ignition with low combustion energy
4. Low ignition with high combustion energy

Subtopic:  Hydrogen Economy |
 50%
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The decreasing order of electrical conductivity of the following aqueous solutions is :
0.1 M Formic acid (A),
0.1 M Acetic acid (B),
0.1 M Benzoic acid (C)

1. A > B > C

2. A > C > B

3. C > B > A

4. C > A > B

Subtopic:  Conductance & Conductivity |
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Given below are the half-cell reactions :

Mn2++2eMn;E=1.18 V2(Mn3++eMn2+);E=+1.51 V

The Eº for 3Mn2+ → Mn + 2Mn3+ will be :

1. – 2.69 V; the reaction will occur

2. – 0.33 V; the reaction will not occur

3. – 0.33 V; the reaction will occur

4. – 2.69 V; the reaction will not occur

Subtopic:  Electrode & Electrode Potential |
 58%
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The reduction potential of hydrogen half-cell will be negative if:

1. P(H2) = 1atm and [H+] = 2.0 M

2. P(H2) = 1 atm and [H+] = 1.0 M

3. P(H2) = 2 atm and [H+] = 1.0 M

4. P(H2) = 2 atm and [H+] = 2.0 M

Subtopic:  Nernst Equation | Relation between Emf, G, Kc & pH |
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For the following cell with hydrogen electrodes at two different pressures p1 and p
Pt(H2) | H+(aq) |Pt (H2)
  p       1M        p2   
emf  is given by:

1. \(\frac{R T}{F} \log _{e} \frac{P_{1}}{p_{2}}\)
2. \(\frac{R T}{2F} \log _{e} \frac{P_{1}}{p_{2}}\)
3. \(\frac{R T}{F} \log _{e} \frac{P_{2}}{p_{1}}\)
4. \(\frac{R T}{2F} \log _{e} \frac{P_{2}}{p_{1}}\)

Subtopic:  Nernst Equation |
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The molar conductivity of 0.05 M NH4Cl is 20 S cm2 mol-1. The molar conductivities of \(NH^+_4\) and \(Cl^-\) ions at infinite dilution are 74 S cm2 mol-1 and 26 S cm2 mol-1, respectively. The dissociation constant of NH4Cl will be: 
1. \(2.5 \times 10^{-3}\) 2. \(2 \times 10^{-3}\)
3. \(2.5 \times 10^{-4}\) 4. \(2 \times 10^{-4}\)
Subtopic:   Kohlrausch Law & Cell Constant |
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The feasible reaction, amongst the following, is 
1.  \(2KCl + Br_2 \rightarrow 2KBr + Cl_2\)
2. \(2KF + I_2 \rightarrow 2KI + F_2\)
3. \(2 KClO_3 + I_2 \rightarrow 2KIO_3 + Cl_2\)
4. \(2KIO_3 + Cl_2 \rightarrow 2KClO_3 + I_2\)
Subtopic:  Electrochemical Series |
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