Q. No.| Assertion (A): | Irrespective of the source, a given compound always contains the same elements in the same proportion. |
| Reason (R): | This law is referred to as the law of multiple proportions. |
| 1. | Both (A) and (R) are true and (R) is the correct explanation of (A). |
| 2. | Both (A) and (R) are true but (R) is not the correct explanation of (A). |
| 3. | (A) is true but (R) is false. |
| 4. | Both (A) and (R) are false. |
| Statement I: | The law of multiple proportions is followed by the gases SO2 and SO3, but not by CO and CO2. |
| Statement II: | Dalton’s theory explains the laws of chemical combination as well as laws of gaseous volumes. |
| 1. | Statement I is correct, and Statement II is correct. |
| 2. | Statement I is incorrect, and Statement II is correct. |
| 3. | Statement I is correct, and Statement II is incorrect. |
| 4. | Statement I is incorrect, and Statement II is incorrect. |
At constant T and P, 5.0 L of SO2 is reacted with 3.0 L of O2 according to the following equation:
2SO2(g) + O2(g) → 2SO3(g)
The volume of the remaining reaction mixture at the completion of the reaction will be:
1. 0.5 L
2. 8.0 L
3. 5.5 L
4. 5 L
| Statement I: | 1 amu is defined as the mass exactly equal to one-twelfth of the mass of one carbon-12 atom. |
| Statement II: | Number of atoms in 8 u of He is 2NA. |
| 1. | Both Statement I and Statement II are correct. |
| 2. | Both Statement I and Statement II are incorrect. |
| 3. | Statement I is correct but Statement II is incorrect. |
| 4. | Statement I is incorrect but Statement II is correct |
The vapour density of a mixture containing \(NO_{2}\) and \(N_{2} O_{4}\) is 38.3. The mole of \(NO_{2}\) in a 100 g mixture is:
[Vapour density = (Molar mass / 2)]
1. 0.437
2. 0.347
3. 0.557
4. 0.663
A mixture of and gas "Y" (mol. wt. 80) in the mole ratio a : b has a mean molecular weight of 40. What would be the mean molecular weight, if the gases are mixed in the ratio b : a under identical conditions? (assume that these gases do not react)
| 1. | 40 | 2. | 48 |
| 3. | 62 | 4. | 72 |
What is the correct ascending order of masses for the following (I to IV)?
(Atomic mass : N=14, O=16 Cu = 63)
I. 1 molecule of oxygen
II. 1 atom of nitrogen
III. 1 x 10-10g molecule-weight of oxygen
IV. 1 x 10-10g atom-weight of copper
Codes
1. II < I < III < IV
2. IV < III < II < I
3. II < III < I < IV
4. III < IV < I < II
| Assertion (A): | 1 g O2 and 1 g O3 have an equal number of oxygen atoms. |
| Reason (R): | O2 and O3 have different molar masses. |
| 1. | Both (A) and (R) are True and (R) is the correct explanation of (A). |
| 2. | Both (A) and (R) are True but (R) is not the correct explanation of (A). |
| 3. | (A) is True but (R) is False. |
| 4. | (A) is False but (R) is True. |
The molecular formula of a commercial resin used for exchanging ions in water softening is . The maximum uptake of ions by the resin when expressed in mole per gram resin is:
\( \mathrm{C}_8 \mathrm{H}_7 \mathrm{SO}_3 \mathrm{Na}+\mathrm{Ca}^{2+} \rightarrow (\mathrm{C}_8 \mathrm{H}_7 \mathrm{SO}_{3}){_2} \mathrm{Ca}+ \mathrm{Na}^{+}\)
1.
2.
3.
4.
The average molar mass of the mixture of and present in the mole ratio of a:b is
20 g mol-1. When the mole ratio is reversed, the molar mass of the mixture will be:
| 1. | 24 gram | 2. | 42 gram |
| 3. | 20 gram | 4. | 15 gram |
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