Consider the following reaction:
\(\mathrm{4 {HNO}_3({l})+3 {KCl}({s})} → \\\mathrm{{Cl}_2({g})+{NOCl}({g})+2 {H}_2 {O}({g})+3 {KNO}_3({s})}\)
How much \(\text{HNO}_3\) (in grams) is required to produce 110.0 g of \(\text{KNO}_3\)?
(Given: Atomic masses of H, O, N, and K are 1, 16, 14, and 39, respectively.)
1. 32.2g
2. 69.4g
3. 91.5g
4. 162.5g