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Q. No.If the gravitational potential on the surface of Earth is \(V_0,\) then potential at a point at a height equal to half of the radius of Earth is:
| 1. | \(\dfrac{V_0}{2}\) | 2. | \(\dfrac{2V_0}{3}\) |
| 3. | \(\dfrac{V_0}{3}\) | 4. | \(\dfrac{3V_0}{2}\) |
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