- 1(current)
Q. No.The mole fraction of glucose (C6H12O6) in an aqueous binary solution is 0.1. The mass percentage of water in it to the nearest integer is:
| 1. | 44% | 2. | 49 % |
| 3. | 47 % | 4. | 41 % |
Subtopic: Concentration Terms & Henry's Law |
58%
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JEE
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NEET 2026 - Target Batch - Vital
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NEET 2026 - Target Batch - Vital
4.5 g of compound A (MW = 90) was used to make 250 mL of its aqueous solution. The molarity of the solution in M is x × 10–1 . The value of x is ________. (Rounded off to the nearest integer)
1. 5
2. 4
3. 2
4. 1
Subtopic: Concentration Terms & Henry's Law |
88%
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JEE
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What is the mole fraction of methyl alcohol in a 5.2 molal aqueous solution of methyl alcohol?
1. 0.100
2. 0.190
3. 0.086
4. 0.050
Subtopic: Concentration Terms & Henry's Law |
69%
From NCERT
JEE
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The molarity of CO2 in a soft drink is 0.01 M. The volume of soft drink is 300 mL. The mass of CO2 in soft drink is:
1. 0.132 g
2. 0.481 g
3. 0.312 g
4. 0.190 g
1. 0.132 g
2. 0.481 g
3. 0.312 g
4. 0.190 g
Subtopic: Concentration Terms & Henry's Law |
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The density of a 3 M NaCl solution is 1 g/mL. The molality of the solution is ‘x’. The value of 2x is:
(Round off to nearest integer)
1. 7
2. 10
3. 13
4. 5
(Round off to nearest integer)
1. 7
2. 10
3. 13
4. 5
Subtopic: Concentration Terms & Henry's Law |
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A sodium chloride (NaCl) solution has a molarity of 3 M. Given that the density of the solution is 1.25 g/mL, its molality will be:
| 1. | 2.90 | 2. | 2.79 |
| 3. | 1.85 | 4. | 3.85 |
Subtopic: Concentration Terms & Henry's Law |
66%
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If the density of an x M solution of NaOH is 1.12 g/mL and its molality is 3 m, determine the value of x.
1. 3.0
2. 2.3
3. 4.0
4. 5.2
1. 3.0
2. 2.3
3. 4.0
4. 5.2
Subtopic: Concentration Terms & Henry's Law |
80%
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JEE
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