In an \(L\text-R\) circuit, the inductive reactance is equal to the resistance \(R\) of the circuit. An emf of \(E = E_0 \cos(\omega t)\) is applied to the circuit. The power consumed by the circuit is:
1. \(\dfrac{E^2_0}{\sqrt{2}R}\) 2. \(\dfrac{E^2_0}{4R}\)
3. \(\dfrac{E^2_0}{2R}\) 4. \(\dfrac{E^2_0}{8R}\)

Subtopic:  Power factor |
 56%
Level 3: 35%-60%
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A series AC circuit has a resistance of \(4~\Omega\) and an inductor of reactance \(3~\Omega\). The impedance of the circuit is \(z_1\). Now when a capacitor of reactance \(6~\Omega\) is connected in series with the above combination, the impedance becomes \(z_2\). Then \(\frac{z_1}{z_2}\) will be:
1. \(1:1\)
2. \(5:4\)
3. \(4:5\)
4. \(2:1\)

Subtopic:  Different Types of AC Circuits |
 87%
Level 1: 80%+
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An inductor \((L)\) and resistance \((R)\) are connected in series with an AC source. The phase difference between voltage \((V)\) and current \((i)\) is \(45^{\circ}.\) If the phase difference between \(V\) and \(i\) remains the same, then the capacitive reactance and impedance of the \(LCR\) circuit will be:
1. \(2R, R\sqrt{2}\)
2. \(R, R\sqrt{2}\)
3. \(R, R\)
4. \(2R, R\sqrt{3}\)

Subtopic:  Different Types of AC Circuits |
 55%
Level 3: 35%-60%
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Alternating current cannot be measured by a DC ammeter because:
1. AC cannot pass through DC Ammeter.
2. AC changes direction.
3. Average value of current for the complete cycle is zero.
4. DC Ammeter will get damaged.
Subtopic:  AC vs DC |
 66%
Level 2: 60%+
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In AC (alternating current) generator, a coil of wire rotates in a magnetic field.
                  
Which of the following would change the potential difference measured by the voltmeter in the system above?
(a) use more turns of wire in the coil.
(b) use thicker wire.
(c) change the speed of rotation.

Choose the correct option from the given ones:
1. (c) only
2. (a), (b) and (c)
3. (a) and (b) only
4. (a) and (c) only
Subtopic:  AC Generator |
 55%
Level 3: 35%-60%
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A transformer has an efficiency of \(90\%\) when working on a \(200\) V and \(3\) kW power supply. If the current in the secondary coil is \(6\) A, the voltage across the secondary coil and the current in the primary coil, respectively, are:
1. \(300\) V, \(15\) A
2. \(450\) V, \(15\) A
3. \(450\) V, \(13.5\) A
4. \(600\) V, \(15\) A

Subtopic:  Transformer |
 74%
Level 2: 60%+
AIPMT - 2014
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The core of a transformer is laminated because:

1. Energy losses due to eddy currents may be minimized
2. The weight of the transformer may be reduced
3. Rusting of the core may be prevented
4. Ratio of voltage in primary and secondary may be increased
Subtopic:  Transformer |
 90%
Level 1: 80%+
AIPMT - 2006
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How much power is dissipated in an \(LCR\) series circuit connected to an \(\text{AC}\) source of emf \( E\)?
1. \(\frac{\varepsilon^{2} R}{\left[R^{2}+\left(L \omega-\frac{1}{C \omega}\right)^{2}\right]}\) 2. \(\frac{\varepsilon^{2} \sqrt{R^{2}+\left(L \omega-\frac{1}{C \omega}\right)^{2}}}{R}\)
3. \(\frac{\varepsilon^{2}\left[R^{2}+\left(L \omega-\frac{1}{C \omega}\right)^{2}\right]}{R}\) 4. \(\frac{\varepsilon^{2}R}{\sqrt{R^{2}+\left(L \omega-\frac{1}{C \omega}\right)^{2}}}\)
Subtopic:  Power factor |
 71%
Level 2: 60%+
AIPMT - 2009
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A coil of inductive reactance of \(31~\Omega\) has a resistance of \(8~\Omega\). It is placed in series with a condenser of capacitive reactance \(25~\Omega\). The combination is connected to an AC source of \(110\) V. The power factor of the circuit is:
1. \(0.56\)
2. \(0.64\)
3. \(0.80\)
4. \(0.33\)

Subtopic:  Power factor |
 87%
Level 1: 80%+
AIPMT - 2006
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A \(220\) V input is supplied to a transformer. The output circuit draws a current of \(2.0\) A at \(440\) V. What is the current drawn by the primary windings of the transformer if the efficiency of the transformer is \(80\%\)?
1. \(3.6\) A
2. \(2.8\) A
3. \(2.5\) A
4. \(5.0\) A

Subtopic:  Transformer |
 76%
Level 2: 60%+
AIPMT - 2010
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