The most common oxidation state for lanthanoids and actinoids is:
1. +5
2. -3
3. +1
4. +3
Which one of the following is a diamagnetic ion?
1. | La3+ | 2. | Lu3+ |
3. | Ce4+ | 4. | All of the above. |
Actinoids show a greater number of oxidation states than lanthanoids because:
1. | 4f- orbitals are more diffused than 5f-orbitals |
2. | Lesser energy difference between 5f, and 6d orbitals than between 4f, and 5d orbitals |
3. | More energy difference between 5f, and 6d orbitals than between 4f, and 5d orbitals |
4. | More reactive nature of the actinoids than the lanthanoids. |
The electronic configuration of the last element of actinoids is :
1. Thorium, Th:
2. Lawrencium, Lr:
3. Neptunium, Np:
4. Protactinium, Pa:
From the following, which is the most basic hydroxide?
1. Ce(OH)3
2. Lu(OH)3
3. Yb(OH)3
4. Tb(OH)3
Give below are some atomic numbers:
29, 59, 74, 95, 102, 104
The atomic numbers of the inner transition elements among the above are :
1. | 29, 59, 74
|
2. | 59, 95, 102
|
3. | 95, 102, 104
|
4. | 59, 74, 95 |