The displacement \((x)\) of a point moving in a straight line is given by; \(x=8t^2-4t.\) Then the velocity of the particle is zero at:
1. | \(0.4\) s | 2. | \(0.25\) s |
3. | \(0.5\) s | 4. | \(0.3\) s |
If the velocity of a particle is \(v=At+Bt^{2},\) where \(A\) and \(B\) are constants, then the distance travelled by it between \(1~\text{s}\) and \(2~\text{s}\) is:
1. | \(3A+7B\) | 2. | \(\frac{3}{2}A+\frac{7}{3}B\) |
3. | \(\frac{A}{2}+\frac{B}{3}\) | 4. | \(\frac{3A}{2}+4B\) |
The position of an object moving along the x-axis is given by, \(x=a+bt^2\) where \(a=8.5\) m, \(b=2.5\) ms-2, and \(t\) is measured in seconds. Its velocity at \(t=2.0\) s will be:
1. \(13\) m/s
2. \(17\) m/s
3. \(10\) m/s
4. \(0\)
For a particle, displacement time relation is given by . Its displacement, when its velocity is zero will be:
1. \(2\) m
2. \(4\) m
3. \(0\)
4. none of the above
The position x of a particle moving along the x-axis varies with time t as x = , where x is in meters and t is in seconds. The particle reverses its direction of motion at:
1. x = 40 m
2. x = 10 m
3. x = 20 m
4. x = 30 m
The relation \(3t = \sqrt{3x} + 6\) describes the displacement of a particle in one direction where \(x\) is in metres and \(t\) in seconds. The displacement, when velocity is zero, is:
1. | \(24\) metres | 2. | \(12\) metres |
3. | \(5\) metres | 4. | zero |
A body in one-dimensional motion has zero speed at an instant. At that instant, it must have:
1. | zero velocity. | 2. | zero acceleration. |
3. | non-zero velocity. | 4. | non-zero acceleration. |
Which of the following four statements is false?
1. | A body can have zero velocity and still be accelerated. |
2. | A body can have a constant velocity and still have a varying speed. |
3. | A body can have a constant speed and still have a varying velocity. |
4. | The direction of the velocity of a body can change when its acceleration is constant. |
A particle moves along a straight line and its position as a function of time is given by \(x= t^3-3t^2+3t+3\)
1. | \(t=1~\text{s}\) and reverses its direction of motion | stops at
2. | \(t= 1~\text{s}\) and continues further without a change of direction | stops at
3. | \(t=2~\text{s}\) and reverses its direction of motion | stops at
4. | \(t=2~\text{s}\) and continues further without a change of direction | stops at
The relation between time and distance is given by , where α and β are constants. The retardation, as calculated based on this equation, will be (assume v to be velocity) :
1.
2.
3.
4.