In a common-emitter transistor amplifier, the audio signal voltage across the collector is 3 V. The resistance of the collector is 3 k$\Omega$. If the current gain is 100 and the base resistance is 2 k$\Omega$, the voltage and power gain of the amplifier are:

1. 200 and 1000

2. 15 and 200

3. 150 and 15000

4. 20 and 2000

An n-p-n transistor is connected in the common base configuration in a given amplifier. A load resistance of 800Ω is connected in the collector circuit and the voltage drop across it is 0.8 V. If the current amplification factor is 0.96 and the input resistance of the circuits is 192 Ω the voltage gain and the power gain of the amplifier will respectively be

1. 3.69,3.84
2. 4,4
3. 4,3.69
4. 4,3.84

Transfer characteristic [output voltage $\left(V_{\mathrm{o}}\right)$ vs input voltage $\left(V_i\right)$] for a base biased transistor in CE configuration is as shown in the figure. For using transistor as a switch, it is used:
                     

1. in region III

2. both in region (I) and (III)

3. in region II

4. in region I

For a transistor, the current amplification factor is 0.8 when it is connected in the common base configuration. The transistor is now connected in common emitter configuration. The change in the collector current when the base current changes by 6 mA, is:
1. 6 mA                       

2. 4.8 mA

3. 24 mA                     

4. 8 mA

For the transistor circuit shown below, if $\mathrm{\beta }$ = 100, the voltage drop between emitter and base is 0.7 V, then the value of ${\mathrm{V}}_{\mathrm{CE}}$ will be:
                  
1. 10 V
2. 5 V
3. 13 V
4. 0 V

In the circuit shown in the figure, the input voltage V_i is 20 V, V_BE = 0, and V_CE = 0. The values of I_B, I_C and $\beta$ are given by:
           

1. ${\mathrm{I}}_{\mathrm{B}}$ $=$ $40$ $\mathrm{\mu A},$ ${\mathrm{I}}_{\mathrm{c}}$ $=$ $10$ $\mathrm{mA},$ $\mathrm{\beta }$ $=$ $250$

2. ${\mathrm{I}}_{\mathrm{B}}$ $=$ $25$ $\mathrm{\mu A},$ ${\mathrm{I}}_{\mathrm{c}}$ $=$ $5$ $\mathrm{mA},$ $\mathrm{\beta }$ $=$ $200$

3. ${\mathrm{I}}_{\mathrm{B}}$ $=$ $20$ $\mathrm{\mu A},$ ${\mathrm{I}}_{\mathrm{c}}$ $=$ $5$ $\mathrm{mA},$ $\mathrm{\beta }$ $=$ $250$

4. ${\mathrm{I}}_{\mathrm{B}}$ $=$ $40$ $\mathrm{\mu A},$ ${\mathrm{I}}_{\mathrm{c}}$ $=$ $5$ $\mathrm{mA},$ $\mathrm{\beta }$ $=$ $125$

In a common-emitter transistor amplifier, the audio signal voltage across the collector is 3V. The resistance of the collector is 3k$\Omega$. If the current gain is 100 and the base resistance is 2k$\Omega$, the voltage and power gain of the amplifier are:

1. 15 and 200

2. 150 and 15000

3. 20 and 2000

4. 200 and 1000

For the CE transistor amplifier, the audio signal voltage across the collector resistance of 2k$\Omega$ is 4V. If the current amplification factor of the transistor is 100 and the base resistance is 1k$\Omega$, then the input signal voltage is:

1.  10 mV

2.  20 mV

3.  30 mV

4.  15 mV

The input signal given to a CE amplifier having a voltage gain of 150 is ${\mathrm{V}}_{\mathrm{i}}=2\cos \left[15\mathrm{t}+\frac{{\displaystyle \mathrm{\pi }}}{{\displaystyle 3}}\right]$. The corresponding output signal will be:

1. $30<mspace\; width="1em"></mspace>\cos <mspace\; width="1em"></mspace>\left[15\mathrm{t}+\frac{\mathrm{\pi }}{3}\right]$

2. $75<mspace\; width="1em"></mspace>\cos <mspace\; width="1em"></mspace>\left[15\mathrm{t}+\frac{2\mathrm{\pi }}{3}\right]$

3. $2<mspace\; width="1em"></mspace>\cos <mspace\; width="1em"></mspace>\left[15\mathrm{t}+\frac{5\mathrm{\pi }}{3}\right]$

4. $300<mspace\; width="1em"></mspace>\cos <mspace\; width="1em"></mspace>\left[15\mathrm{t}+\frac{4\mathrm{\pi }}{3}\right]$