A child pulls a box with a force of at an angle of above the horizontal. Then the horizontal
and vertical components of the force will be:
1. 100 N, 175 N
2. 86.6 N, 100 N
3. 100 N, 86.6 N
4. 100 N, 0 N
The linear velocity of a rotating body is given by , where is the angular velocity and r is the radius vector. The angular velocity of a body, and their radius vector is will be:
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A body is moving according to the equation where x represents displacement and a, b and c are constants. The acceleration of the body is: (\(Given: a=\frac{d^2x}{dt^2}\))
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If \(\vec{a}\) is a vector and \(x\) is a non-zero scalar, then which of the following is correct?
1. \(x\vec{a}\) is a vector in the direction of \(\vec{a}\)
2. \(x\vec{a}\) is a vector collinear to \(\vec{a}\)
3. \(x\vec{a}\) and \(\vec{a}\) have independent directions
4. \(x\vec{a}\) is a vector perpendicular to \(\vec{a}\)
and are two vectors and θ is the angle between them. If , then the value of θ will be:
1. 60o
2. 45o
3. 30o
4. 90o
The acceleration of a particle is given by a=3t at t=0, v=0, x=0. The velocity and displacement at t = 2 sec will be: (\(Here, a=\frac{dv}{dt}~ and~v=\frac{dx}{dt}\))
1. 6 m/s, 4 m
2. 4 m/s, 6 m
3. 3 m/s, 2 m
4. 2 m/s, 3 m
At what angle must the two forces (x + y) and (x – y) act so that the resultant comes out to be ?
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In the given figure
1. Angle between and is
2. Angle between and is
3. Angle between and is
4. Angle between and is
If vector and are functions of time, then the value of t at which they are orthogonal to each other will be:
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