Match List I with List II.
List I
(Spectral Lines of Hydrogen for transitions from)
List II
(Wavelength (nm))
\(\mathrm{A.}\) \(n_2=3\)  to \(n_1=2\)  \(\mathrm{I.}\) \(410.2\)
\(\mathrm{B.}\) \(n_2=4\)  to \(n_1=2\)  \(\mathrm{II.}\) \(434.1\)
\(\mathrm{C.}\) \(n_2=5\)  to \(n_1=2\)  \(\mathrm{III.}\) \(656.3\)
\(\mathrm{D.}\) \(n_2=6\) to \(n_1=2\)  \(\mathrm{IV.}\) \(486.1\)
Choose the correct answer from the options given below:
1. \(\mathrm{A - III, B - IV, C - II, D - I}\)
2. \(\mathrm{A - IV, B - III, C - I, D - II}\)
3. \(\mathrm{A - I, B - II, C - III, D - IV}\)
4. \(\mathrm{A - II, B - I, C - IV, D - III}\)
Subtopic:  Spectral Series |
 62%
From NCERT
NEET - 2024
Please attempt this question first.
Hints
Please attempt this question first.

Given below are two statements:
Statement I: Atoms are electrically neutral as they contain equal number of positive and negative charges.
Statement II: Atoms of each element are stable and emit their characteristic spectrum.
In the light of the above statements, choose the most appropriate answer from the options given below:
1. Both Statement I and Statement II are incorrect.
2. Statement I is correct but Statement II is incorrect.
3. Statement I is incorrect but Statement II is correct.
4. Both Statement I and Statement II are correct.
Subtopic:  Spectral Series |
From NCERT
NEET - 2024
Please attempt this question first.
Hints
Please attempt this question first.

Match List-I with List-II 
     List-I
   (Series)
         List-II
(Wave number in cm-1)
A. Balmer series I. \( R\left(\frac{1}{1^2}-\frac{1}{n^2}\right) \)
B. Lyman series II. \( R\left(\frac{1}{4^2}-\frac{1}{n^2}\right) \)
C. Brackett series III. \( R\left(\frac{1}{5^2}-\frac{1}{n^2}\right) \)
D. Pfund series  IV. \( R\left(\frac{1}{2^2}-\frac{1}{n^2}\right)\)
Choose the correct answer from the options given below
1. A-I,B-IV,C-III,D-II
2. A-II, B-III, C-IV,D-I
3. A-IV, B-I, C-II, D-III
4. A-III, B-II, C-I,D-IV
 
Subtopic:  Spectral Series |
 72%
From NCERT
NEET - 2024
Please attempt this question first.
Hints
Please attempt this question first.

advertisementadvertisement

In hydrogen spectrum, the shortest wavelength in the Balmer series is \(\lambda\). The shortest wavelength in the Bracket series is:
1. \(16\lambda\)
2. \(2\lambda\)
3. \(4\lambda\)
4. \(9\lambda\)
Subtopic:  Spectral Series |
 59%
From NCERT
NEET - 2023
Please attempt this question first.
Hints
Please attempt this question first.

The wavelength of Lyman series of hydrogen atom appears in:
1. visible region
2. far infrared region
3. ultraviolet region
4. infrared region
Subtopic:  Spectral Series |
 77%
From NCERT
NEET - 2023
Please attempt this question first.
Hints
Please attempt this question first.