Q. No.A liquid drop of radius \(R \) is divided into \(27\) identical drops. If the surface tension of the drops is \(T,\) then the work done in this process is:
1. \(4\pi R^2T \)
2. \(3\pi R^2T\)
3. \(8\pi R^2T\)
4. \(\dfrac{1}{8}\pi R^2T\)
1. \(4\pi R^2T \)
2. \(3\pi R^2T\)
3. \(8\pi R^2T\)
4. \(\dfrac{1}{8}\pi R^2T\)
Subtopic: Â Surface Tension |
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The spherical shape of raindrop is due to:
| 1. | the density of the liquid | 2. | the surface tension |
| 3. | the atmospheric pressure | 4. | gravity |
Subtopic: Â Surface Tension |
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Pressure inside a soap bubble is greater than the pressure outside by an amount : (given : \(R\) = Radius of bubble, \(S\) = Surface tension of bubble)
1. \(4R/S\)
2. \(4S/R\)
3. \(2S/R\)
4. \(S/R\)
Subtopic: Â Surface Tension |
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When the ends of a glass tube are heated, they gradually become spherical in shape. This phenomenon occurs due to:
1. tension
2. surface tension
3. pressure
4. gravity
1. tension
2. surface tension
3. pressure
4. gravity
Subtopic: Â Surface Tension |
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The excess pressure inside a soap bubble is thrice the excess pressure inside a second soap bubble. The ratio between the volume of the first and the second bubble is:
1. \(1:81\)
2. \(1:9\)
3. \(1:27\)
4. \(1:3\)
Subtopic: Â Surface Tension |
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Given below are two statements:
| Assertion (A): | Clothes containing oil or grease stains cannot be cleaned by water wash |
| Reason (R): | Because the angle of contact between the oil/grease and water is obtuse. |
| 1. | Both (A) and (R) are True and (R) is the correct explanation of (A). |
| 2. | Both (A) and (R) are True but (R) is not the correct explanation of (A). |
| 3. | (A) is True but (R) is False. |
| 4. | (A) is False but (R) is True. |
Subtopic: Â Surface Tension |
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If work \(W\) is done in blowing a bubble of radius \(R\) from a soap solution, then the work done in blowing a bubble of radius \(2R\) from the same solution is:
1. \(W/2\)
2. \(2W\)
3. \(4W\)
4. \(2\dfrac{1}{3}W\)
Subtopic: Â Surface Tension |
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For a soap bubble, the difference between the inside pressure and the outside pressure is given by:
(where \(r\) is the radius of the bubble and \(S\) is the surface tension of the soap solution)
(where \(r\) is the radius of the bubble and \(S\) is the surface tension of the soap solution)
| 1. | \(\dfrac{2S}{r}\) | 2. | \(\dfrac{4S}{r}\) |
| 3. | \(\dfrac{S}{r}\) | 4. | \(\dfrac{S}{2r}\) |
Subtopic: Â Surface Tension |
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The surface tension of a soap solution is \(2 \times 10^{-2}\) N/m. If a soap bubble with a radius of \(4\) cm is blown, the amount of work done is:
1. \(4\pi \times 10^{-6}~\text{J}\)
2. \(2.56\pi \times 10^{-4}~\text{J}\)
3. \(16\pi \times 10^{-5}~\text{J}\)
4. \(16\pi \times 10^{-6}~\text{J}\)
Subtopic: Â Surface Tension |
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Level 1: 80%+
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Given below are two statements:
| Assertion (A): | Smaller drops of water resist deformation forces better than larger drops. |
| Reason (R): | Excess pressure inside the drop is inversely proportional to its radius. |
| 1. | Both (A) and (R) are True and (R) is the correct explanation of (A). |
| 2. | Both (A) and (R) are True but (R) is not the correct explanation of (A). |
| 3. | (A) is True but (R) is False. |
| 4. | (A) is False but (R) is True. |
Subtopic: Â Surface Tension |
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Level 2: 60%+
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