The displacement \(x\) (in \(\text m\)) of a particle of mass \(m\) (in \(\text{kg}\)) moving in one dimension under the action of a force, is related to time \(t\) (in \(\text s\)) by; \(t = (\sqrt x +3 ).\) The displacement of the particle when its velocity is zero will be:
1.
\(4~\text m\)
2.
zero
3.
\(6~\text m\)
4.
\(2~\text m\)
Add Note
Subtopic: Â Instantaneous Speed & Instantaneous Velocity |
 89%
Level 1: 80%+
NEET - 2013
Other Reason
Highlight in NCERT
Hints
Upgrade Your Plan
Upgrade now and unlock your full question bank experience with daily practice.
A particle moves along a straight line \(OX.\) At a time \(t\) (in seconds), the displacement \(x\) (in metres) of the particle from \(O\) is given by \(x= 40 +12t-t^3.\) How long would the particle travel before coming to rest?
1.
\(24~\text m\)
2.
\(40~\text m\)
3.
\(56~\text m\)
4.
\(16~\text m\)
Add Note
Subtopic: Â Instantaneous Speed & Instantaneous Velocity |
Level 3: 35%-60%
AIPMT - 2006
Other Reason
Highlight in NCERT
Hints
Links
Upgrade Your Plan
Upgrade now and unlock your full question bank experience with daily practice.