A compound is treated with NaNH₂ to give sodium salt. Identify the compound.                      

1. C₂H₂                  2. C₆H₆

3. C₂H₆                  4. C₂H₄

The reaction of toluene with Cl₂ in the presence of FeCl₃ gives 'X' and reaction in presence of presence of light gives 'Y'. Thus 'X' and 'Y' are                                            

(a) X= benzal chloride, Y=o-chlorotoluene

(b) X=m-chlorotoluene, Y=p-chlorotoluene

(c) X=o and p-chlorotoluene, Y= trichloromethyl benzene

(d) X= benzyl hloride, Y=m-chlorotoluene

Propene, CH₃-CH=CH₂ can be converted into 1-propanol by oxidation. Indicate which set of reagents amongst the following is ideal to effect the above conversion?                                       

1. KMnO₄(alkaline)

2. Osmium tetroxide (OsO₄/CH₂Cl₂)

3. B₂H₆ and alk H₂O₂

4. O₃/Zn

In Friedel-Craft's synthesis of toluene, the reactants in addition to anhydrous AlCl₃ are           

1. C₆H₅Cl + CH₄

2. C₆H₅Cl + CH₃Cl

3. C₆H₆ + CH₄

4. C₆H₆ + CH₃Cl

3-hexyne can be converted to trans-3-hexene by the action of:

1. ${\mathrm{H}}_2$ - Pd/ ${\mathrm{BaSO}}_4$                       2. Li-Liq. ${\mathrm{NH}}_3$

3. ${\mathrm{H}}_2$ - Pt ${\mathrm{O}}_2$                                4. ${\mathrm{NaBH}}_4$

Which one of the following has the shortest carbon-carbon bond length?

1. Benzene                                  2. Ethene

3. Ethyne                                    4. Ethane

The reaction of HBr with propene in the presence of peroxide gives:

1. Iso-propyl bromide

2. 3-Bromo propane

3. Allyl bromide

4. n-Propyl bromide

The reaction of toluene with ${\mathrm{Cl}}_2$ in the presence of ${\mathrm{FeCl}}_3$ gives 'X' and reaction in presence of light gives 'Y'. Thus, 'X' and  'Y' are

1. X = benzal chloride, Y= o-chlorotoluene

2. X = m-chlorotoluene, Y= p-chlorotoluene

3. X = o and p-chlorotoluene, Y = trichloromethyl benzene

4. X = benzal chloride, Y = m-chlorotoluene

In the reaction, ${\mathrm{C}}_6{\mathrm{H}}_5{\mathrm{CH}}_3\stackrel{\mathrm{Oxidation}}{\to }$A $\stackrel{\mathrm{NaOH}}{\to }$B$\underset{∆}{\overset{\mathrm{Soda} \mathrm{lime}}{\to }}$C 

the product C is:

1. ${\mathrm{C}}_6{\mathrm{H}}_5\mathrm{OH}$                              2. ${\mathrm{C}}_6{\mathrm{H}}_6$

3. ${\mathrm{C}}_6{\mathrm{H}}_5\mathrm{COONa}$                        4. ${\mathrm{C}}_6{\mathrm{H}}_5\mathrm{ONa}$

Which is the most suitable reagent among the following to distinguish compound (III) from rest of the compounds?

I. ${\mathrm{CH}}_3-\mathrm{C}\equiv \mathrm{C}-{\mathrm{CH}}_3$

II. ${\mathrm{CH}}_3-{\mathrm{CH}}_2-{\mathrm{CH}}_2-{\mathrm{CH}}_3$

III. ${\mathrm{CH}}_3-{\mathrm{CH}}_2-\mathrm{C}\equiv \mathrm{CH}$

IV. ${\mathrm{CH}}_3-\mathrm{CH}={\mathrm{CH}}_2$

1. ${\mathrm{Br}}_2$/${\mathrm{CCl}}_4$                                       

2. ${\mathrm{Br}}_2$/${\mathrm{CH}}_3\mathrm{COOH}$

3. Alk.${\mathrm{KMnO}}_4$                                     

4. Ammoniacal ${\mathrm{AgNO}}_3$