If in a \(\mathrm{p\text-n}\) junction, a square input signal of \(10\) V is applied as shown, then the output across \(R_L\) will be:
1. | 2. | ||
3. | 4. |
1. | \(0^\circ-90^\circ\) | 2. | \(90^\circ-180^\circ\) |
3. | \(0^\circ-180^\circ\) | 4. | \(0^\circ-360^\circ\) |
The peak voltage in the output of a half-wave diode rectifier fed with a sinusoidal signal without a filter is \(10\) V. The DC component of the output voltage is:
1. \(\frac{10}{\pi }\) V
2. \(10\) V
3. \(\frac{20}{\pi }\) V
4. \(\frac{10}{\sqrt{2}}\) V
1. \(0\) V
In the circuit given below, if \(V(t)\) is the sinusoidal voltage source, then the voltage drop \(V_{AB}(t)\) across the resistance \(R\):
1. | is half-wave rectified. |
2. | is full-wave rectified. |
3. | has the same peak value in the positive and negative half-cycles. |
4. | has different peak values during the positive and negative half-cycles. |